Get the last column of a selection

DataBlake

Well-known Member
Joined
Jan 26, 2015
Messages
781
Office Version
  1. 2016
Platform
  1. Windows
I want to store lastCol as a variable equal to the last column in the current selection

Code:
Sub selectionEDIT()
Dim sSelect As Range
Dim lastCol As Long
Dim lastRow As Long

Set sSelect = Selection
lastCol = sSelect.SpecialCells(xlCellTypeLastCell).Column
lastRow = sSelect.SpecialCells(xlCellTypeLastCell).Row

but with this code the range of the selection doesnt seem to be doing anything. it just counts the entirety of the worksheet's columns.
where if i have data from a1:m7 and i select d1:h5 the lastCol value should be 5 and the row be 5.

what do?
 

Excel Facts

How can you turn a range sideways?
Copy the range. Select a blank cell. Right-click, Paste Special, then choose Transpose.
How about
Code:
lastCol = sSelect.Columns.Count + sSelect.Column - 1
lastRow = sSelect.Rows.Count + sSelect.Row - 1
 
Upvote 0
can you explain the logic behind the "+sSelect.Column - 1" ?
and why this works and every other form of this seems to fail in this situation?
works perfectly though, thank you.
 
Upvote 0
If you select C3:G7 the count of both columns & rows will give 5, so to get to 7 you have to add the 1st column/row number (in this case 3) which gives 8 & then subtract 1
 
Upvote 0
that is unnecessarily complicated :confused: oh excel. . .
thanks for the info Fluff.
 
Upvote 0
You're welcome & thanks for the feedback
 
Upvote 0
If you think that's complicated how about
Code:
Sub Blakeskate()
Dim sSelect As Range
Dim lastCol As Long
Dim lastRow As Long

Set sSelect = Selection
lastCol = Split(sSelect.Address(, , xlR1C1), "C")(2)
lastRow = Split(Split(sSelect.Address(, , xlR1C1), "R")(2), "C")(0)
End Sub
:)
 
Upvote 0

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