General location and Restrict location

RZoig

New Member
Joined
Jul 10, 2013
Messages
48
Office Version
  1. 365
Platform
  1. Windows
Hello,

I've searched several threads but I couldn´t find one that could help.

I'm trying to find a formula and a VBA function that is able to return the location of a string in a sheet (A) and also within a restricted area (B).

This is what I want for each Output (A and B) with 16.03 for Reference Input:

[TABLE="width: 421"]
<tbody>[TR]
[TD="colspan: 3"][TABLE="width: 421"]
<tbody>[TR]
[TD="colspan: 3"]A. General reference[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD]A[/TD]
[TD]B[/TD]
[TD]C[/TD]
[TD]D[/TD]
[TD]E[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]8.00[/TD]
[TD]8.30[/TD]
[TD]8.15[/TD]
[TD]8.05[/TD]
[TD]9.00[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]12.05[/TD]
[TD]12.15[/TD]
[TD]12.10[/TD]
[TD]12.20[/TD]
[TD]13.00[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]14.00[/TD]
[TD]14.02[/TD]
[TD]14.05[/TD]
[TD]14.08[/TD]
[TD]14.40[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]16.01[/TD]
[TD]16.05[/TD]
[TD]16.03[/TD]
[TD]15.59[/TD]
[TD]16.20[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]18.07[/TD]
[TD]18.10[/TD]
[TD]18.08[/TD]
[TD]18.15[/TD]
[TD]17.56[/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]20.02[/TD]
[TD]20.12[/TD]
[TD]20.20[/TD]
[TD]20.10[/TD]
[TD]21.00[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD]REF->[/TD]
[TD]16.03[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD]Output ->[/TD]
[TD]C4[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD="colspan: 3"]B. Restricted reference[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD]2A[/TD]
[TD]3A[/TD]
[TD]4A[/TD]
[TD]5A[/TD]
[TD]6A[/TD]
[/TR]
[TR]
[TD]PHA1[/TD]
[TD]8.00[/TD]
[TD]8.30[/TD]
[TD]8.15[/TD]
[TD]8.05[/TD]
[TD]9.00[/TD]
[/TR]
[TR]
[TD]PHA2[/TD]
[TD]12.05[/TD]
[TD]12.15[/TD]
[TD]12.10[/TD]
[TD]12.20[/TD]
[TD]13.00[/TD]
[/TR]
[TR]
[TD]PHA3[/TD]
[TD]14.00[/TD]
[TD]14.02[/TD]
[TD]14.05[/TD]
[TD]14.08[/TD]
[TD]14.40[/TD]
[/TR]
[TR]
[TD]PHA4[/TD]
[TD]16.01[/TD]
[TD]16.05[/TD]
[TD]16.03[/TD]
[TD]15.59[/TD]
[TD]16.20[/TD]
[/TR]
[TR]
[TD]PHA5[/TD]
[TD]18.07[/TD]
[TD]18.10[/TD]
[TD]18.08[/TD]
[TD]18.15[/TD]
[TD]17.56[/TD]
[/TR]
[TR]
[TD]PHA6[/TD]
[TD]20.02[/TD]
[TD]20.12[/TD]
[TD]20.20[/TD]
[TD]20.10[/TD]
[TD]21.00[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD]REF->[/TD]
[TD]16.03[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD]Output ->[/TD]
[TD] 4A.PHA4[/TD]
[/TR]
</tbody>[/TABLE]
[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

So:
In 'A' I want the location of 16.03 in a Excel sheet (C4 in my example)
In 'B' I want references of 16.03 within a table separated with a '.' (4A.PHA4 in my example).

A formula and a VBA function solution would be super great, but only the formula would do nicely!

Thank You
Rui
 

Excel Facts

Did you know Excel offers Filter by Selection?
Add the AutoFilter icon to the Quick Access Toolbar. Select a cell containing Apple, click AutoFilter, and you will get all rows with Apple
A:
Code:
=if(countif($a$1:$e$6,$f$9)<>1,"-",char(code("A")-1+sumproduct(column($a$1:$e$6)*($a$1:$e$6=$f$9)))&sumproduct(row($a$1:$e$6)*($a$1:$e$6=$f$9)))
B:
Code:
=if(countif($b$2:$f$7,$f$9)<>1,"-",index($1:$1,sumproduct(column($b$2:$f$7)*($b$2:$f$7=$f$9)))&"."&index($a:$a,sumproduct(row($b$2:$f$7)*($b$2:$f$7=$f$9))))
 
Last edited:
Upvote 0
Stunnrock,

For the time being let´s suppose we're dealing with unique records, i suppose.

Code B:
Fantastic. I'm still depicting what you've done, but it works fine.

Code A:
Something's missing or I adjusted poorly (I use ';' in my regional settings instead of ',') . Result was a minus symbol (-).
No 'C4' as output.

Thanks!
Could you help me a little bit more with A?
 
Upvote 0
Stunnrock

Code A:
Looked again and "or I adjusted poorly" is the right answer. So, amazing. Thank you! It worked of course.

Now I'll have to find how SumProduct is related to find strings! I use it only for calculations not as a reference tool!
How Odd!!

Thanks again!
Rui
 
Upvote 0

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