formula is returning #VALUE! instead of ""

Sean15

Well-known Member
Joined
Jun 25, 2005
Messages
719
Office Version
  1. 2010
Platform
  1. Windows
Hello:

IFERROR(INDEX($E$3:$E$39,MATCH(B50,$B$3:$B$39,0)),"")*-1


This formula above is returning #VALUE ! if value in B50, is not found in range $B$3:$B$39

When I remove *-1, formula is returning "" but I need to have *-1 in formula.

Can someone adjust formula so it returns "" when *-1 is retained in formula.

Thanks for your help.


Regards,

Sean
 

Excel Facts

Pivot Table Drill Down
Double-click any number in a pivot table to create a new report showing all detail rows that make up that number
Maybe this:

Code:
=IFERROR(INDEX($E$3:$E$39,MATCH(B50,$B$3:$B$39,0))[B][COLOR=#ff0000]*-1[/COLOR][/B],"")
 
Upvote 0

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