Formula calculate minutes.

asyamonique

Well-known Member
Joined
Jan 29, 2008
Messages
1,286
Office Version
  1. 2013
Platform
  1. Windows
Code:
=(F3-E3)*1440
Hello,
Above formula gives me the time calulation as minutes of between two cells.
Can you please give me solution to fix that problem given below?

[TABLE="width: 300"]
<tbody>[TR]
[TD="class: xl65, width: 100"]6:11 PM[/TD]
[TD="class: xl65, width: 100"]6:55 AM[/TD]
[TD="class: xl63, width: 100"]-676
[/TD]
[/TR]
</tbody>[/TABLE]

should not show the minutes as negative!

Many Thanks
 

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I wrote that backwards. 6:55AM is a smaller value than 6:11PM. In military time that would be 6:55 - 18:11
 
Upvote 0
6:11 is a lower value than 6:55. Written in military time it would be 6:55 - 18:11.
I am not sure what you are trying to say here as the formula you asked about already assumed that.

Did you try the formula I posted in Message #2 yet?
 
Upvote 0
I was answering the original posters question as to why the answer is negative. He stated that the answer should not be negative. He was subtracting a larger value (6:11PM/18:11) from a smaller value (6:55AM)
 
Upvote 0
I was answering the original posters question as to why the answer is negative. He stated that the answer should not be negative. He was subtracting a larger value (6:11PM/18:11) from a smaller value (6:55AM)
I am sorry... I mistook you for being the OP (your double post fooled me, but my fault for not looking back).
 
Upvote 0
If both times are always the same day, maybe ...

=(MAX(E3,F3)-MIN(E3,F3))*1440

M.
 
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[TABLE="width: 436"]
<colgroup><col><col span="2"><col></colgroup><tbody>[TR]
[TD]1)[/TD]
[TD]10:55 PM[/TD]
[TD]12:55 AM[/TD]
[TD]120[/TD]
[/TR]
[TR]
[TD]2)[/TD]
[TD]10:55 PM[/TD]
[TD]12:55 AM[/TD]
[TD]1,320[/TD]
[/TR]
</tbody>[/TABLE]

1)
Code:
=MOD(1440*(F14-E14),1440)

2)
Code:
=(MAX(E15,F15)-MIN(E15,F15))*1440


Hello All,
Sorry for late post.
Rick's formula helped me so far.
Other formula gives wrong result.
Thanks.
 
Last edited:
Upvote 0

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