format of sheetname in cell is stopping my formula.

GingerStepChild

New Member
Joined
Oct 27, 2016
Messages
28
Hi,

In a cell G19 I have the following to get the sheetname:

=MID(CELL("filename",A1),FIND("]",CELL("filename",A1))+1,20)

The format type is General but all the sheetnames will be numbers.

This sheetname value is manually entered into column A of a table on another sheet called 'Summary'. Type is also "General'

There are 4 columns in the table and I require data from 2 other columns which I get from using an Index/Match

=INDEX(Summary!$B$6:$B$24,MATCH($G$19,Summary!A6:A24,0))
=INDEX(Summary!$C$6:$C$24,MATCH($G$19,Summary!A6:A24,0))

So far so good.

My problem is when I reference the cells that has the sheetname formula, G19 it returns #N/A, which makes me sad.

When I change my reference cell to G18 it returns the values I need.

I do note that when I am checking the formula the G19 value is "2017010" (with quotes) while G18 is 2017010 without quotes.

So, what do I need to do to the sheetname formula cell G19 so my index match works correctly. I have been sniffing about INDIRECT but am not sure I understand it correctly.

Thanks in advance for your help.
 

Excel Facts

Waterfall charts in Excel?
Office 365 customers have access to Waterfall charts since late 2016. They were added to Excel 2019.
1. Any time you use LEFT/MID/RIGHT, the answer will always be text, even if it looks like a number
2. Formatting a text cell to any numeric format (general, fixed etc) wll not change the actual contents of that cell

Try this instead...
=INDEX(Summary!$B$6:$B$24,MATCH(--$G$19,Summary!A6:A24,0))
 
Upvote 0
Your MID() is returning a text number. -- forces a text number to be a real number
Just to add to Ford's explanation...

When you involve a "text number" in a mathematical operation, Excel will convert that "text number" to a "real number" in order to be able to complete the mathematical operation. When you write, as an example, -5 what you really have done is multiply 5 times -1. When you write --5 what you have is -1 times -1 times 5... -1 times -1 mathematically calculates to +1 and +1 times any value (5 in my example's case) is just that value. So, the double minus in front of a "text number" simply multiply it by +1 which simply returns the number as a real number. The same effect could be achieved by using 1* (multiply by 1) or 0+ (add zero) as they do the same thing as -- does... change the number from a "text number" to a "real number" without changing the value itself in any way. Once this conversion is done, the MATCH function is able to search for a real number in a range of real numbers.
 
Upvote 0

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