findnext

fraufreda

Board Regular
Joined
Oct 14, 2010
Messages
190
Hi.
I'm trying to lookup each value of table1 in table2 giving the second column. In table2 data is sorted.

TABLE1...

[table="width: 500, class: grid, align: left"]
[tr]
[td]LOOKUP VALUE[/td]
[td]RESULT[/td]
[/tr]
[tr]
[td]A[/td]
[td]A1[/td]
[/tr]
[tr]
[td]A[/td]
[td]A2[/td]
[/tr]
[tr]
[td]A[/td]
[td]A3[/td]
[/tr]
[tr]
[td]A[/td]
[td]A4[/td]
[/tr]
[tr]
[td]B[/td]
[td]B1[/td]
[/tr]
[tr]
[td]B[/td]
[td]B2[/td]
[/tr]
[tr]
[td]B[/td]
[td]B3[/td]
[/tr]
[tr]
[td]C[/td]
[td]C1[/td]
[/tr]
[tr]
[td]B[/td]
[td]B1[/td]
[/tr]
[tr]
[td]B[/td]
[td]B2[/td]
[/tr]
[tr]
[td]B[/td]
[td]B3[/td]
[/tr]
[/table]

TABLE2..

[table="width: 500, class: grid, align: left"]
[tr]
[td]COL1[/td]
[td]COL2[/td]
[/tr]
[tr]
[td]A[/td]
[td]A1[/td]
[/tr]
[tr]
[td]A[/td]
[td]A2[/td]
[/tr]
[tr]
[td]A[/td]
[td]A3[/td]
[/tr]
[tr]
[td]A[/td]
[td]A4[/td]
[/tr]
[tr]
[td]B[/td]
[td]B1[/td]
[/tr]
[tr]
[td]B[/td]
[td]B2[/td]
[/tr]
[tr]
[td]B[/td]
[td]B3[/td]
[/tr]
[tr]
[td]C[/td]
[td]C1[/td]
[/tr]
[/table]

I TRIED TO USE FINDNEXT TO GIVE ME THE SECOND COL IN THE RESULT BUT IT IS NOT WORKING AND TAKES A LOT OF TIME.

Code:
Dim ws As Worksheet
Dim LRB As Long
Dim cell As Range
Dim Orng As Range
Dim iCounter As Integer
Dim LOOKUPRng As String

Set ws = Sheets("BOM")

   
     LRB = Sheets("bom").Cells(Rows.Count, "F").End(xlUp).Row
    
    With Range("Table5[out]")
            LOOKUPRng = .Find(ComboBox2.Value, , xlValues).Offset(0, 9).Value & "[LOOKUP VALUE]" 
    End With

    For Each cell In ws.Range("A2:A" & LRB)
        With Range(LOOKUPRng)
            Set Orng = .Find(cell.Value, , xlValues)
                iCounter = 2
                Do
                             If Not Orng Is Nothing Then
                                ws.Cells(iCounter, 2).Value = Orng.Offset(0, 1).Value
                                Set Orng = .FindNext(Orng)
                            End If
                Loop While iCounter <= LRB
        End With
    Next
 

Excel Facts

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[TABLE="width: 894"]
<colgroup><col span="2"><col span="10"></colgroup><tbody>[TR]
[TD]A[/TD]
[TD]A1[/TD]
[TD][/TD]
[TD="align: right"]1[/TD]
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[/TR]
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[TD]B[/TD]
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[TD]B[/TD]
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[/TR]
[TR]
[TD]C[/TD]
[TD]C1[/TD]
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[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]B[/TD]
[TD]B1[/TD]
[TD][/TD]
[TD="align: right"]1[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
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[TD][/TD]
[/TR]
[TR]
[TD]B[/TD]
[TD]B2[/TD]
[TD][/TD]
[TD="align: right"]2[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
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[/TR]
[TR]
[TD]B[/TD]
[TD]B3[/TD]
[TD][/TD]
[TD="align: right"]3[/TD]
[TD][/TD]
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[/TR]
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[/TR]
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[/TR]
[TR]
[TD]COL1[/TD]
[TD]COL2[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
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[/TR]
[TR]
[TD]A[/TD]
[TD]A1[/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 6"]I used a helper column to count same letter sequences[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]A[/TD]
[TD]A2[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
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[TD][/TD]
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[/TR]
[TR]
[TD]A[/TD]
[TD]A3[/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 4"]then this macro populated B1:B11[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]A[/TD]
[TD]A4[/TD]
[TD][/TD]
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[/TR]
[TR]
[TD]B[/TD]
[TD]B1[/TD]
[TD][/TD]
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[TD="colspan: 2"]Sub Macro4()[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]B[/TD]
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[TD]'[/TD]
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[/TR]
[TR]
[TD]B[/TD]
[TD]B3[/TD]
[TD][/TD]
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[TD="colspan: 2"]' Macro4 Macro[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]C[/TD]
[TD]C1[/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 4"]' Macro recorded 02/10/2017 by bob[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
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[TD]'[/TD]
[TD][/TD]
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[TD][/TD]
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[/TR]
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[TD]'[/TD]
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[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 2"] For j = 1 To 11[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 2"] letter = Cells(j, 1)[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 3"] numnum = Cells(j, 4)[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD="colspan: 2"] For z = 16 To 23[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
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[/TR]
[TR]
[TD][/TD]
[TD][/TD]
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[TD][/TD]
[TD="colspan: 5"] If Cells(z, 1) = letter Then GoTo 50 Else GoTo 100[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
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[TD="colspan: 3"]50 mynum = mynum + 1[/TD]
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[/TR]
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[TD="colspan: 6"] If mynum = numnum Then Cells(j, 2) = Cells(z, 2): GoTo 200[/TD]
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[/TR]
[TR]
[TD][/TD]
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[TD="colspan: 2"]100 Next z[/TD]
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[TD="colspan: 2"]200 mynum = 0[/TD]
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[TD] Next j[/TD]
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[TD]End Sub[/TD]
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</tbody>[/TABLE]
 
Upvote 0
yes I suppose, I would put some coding in the front of the macro to produce an array with the helper column numbers in it.

maybe
dim numnum (20)
for y= 1 to 11
numnum(y)=right(cells(y,2),1)
next y

and If mynum = numnum(J) then....

delete row 3 of course
 
Upvote 0

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