Finding a value based on row position

pnr8uk

New Member
Joined
Oct 6, 2018
Messages
19
Hello All

A bit of a long shot this one and I've tried so many things to get it working including MATCH, VLOOKUP, INDEX and a combination of all of them however I simply can't get what I am attempting to work and just wondered if it is even possible.


I have a worksheet set up with as below - the figures should probably be considered text
as the tick values (increments) change so much as the numbers get higher it's even trickier to do maths on the values.

[TABLE="width: 500"]
<tbody>[TR]
[TD]Current Value[/TD]
[TD]+ No Ticks[/TD]
[TD]New Value[/TD]
[/TR]
[TR]
[TD]1.01[/TD]
[TD]10[/TD]
[TD]XX[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

So when I change the number of ticks the new value should be returned...

The tick numbers are located on a separate sheet and look like this.. This is the first 10 rows, the tick sizes change after 1.1 so it not possible to simply use maths to add up.

[TABLE="width: 500"]
<tbody>[TR]
[TD]1.01
[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.02[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.03[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.04[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.05[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.06[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.07[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.08[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.09[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.1
[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.11[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.12[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1.13[/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

All I want to do is when I put in 1.01 in the first column is move down 10 rows (for instance)
and return the value in my tenth row above the 1.01 which would be 1.1

So it's a sort of a VLOOKUP up vertically rather horizontally I guess.

Any ideas how to look up a value then return a row +XX rows further down?

Many thanks...
 

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The =SQRT(25) is a square root. For a cube root, use =125^(1/3). For a fourth root, use =625^(1/4).
Hi,

Have you tried

=Offset(A1,10,0)

Hope this will help
 
Upvote 0
Oh my goodness me!! That is so simple and it works!! Thank you so much I have been so deep into this including VBA...

Thanks you once again my friend.
 
Upvote 0

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