Finding 1st and last occurrence

michaelsmith559

Well-known Member
Joined
Oct 6, 2013
Messages
881
Office Version
  1. 2013
  2. 2007
I am trying to find a formula/code that will find the 1st and last occurrence of the 2nd value. Needs to be easily changed for 3rd, 4th, 5th values as well. Below is what I am looking to accomplish. The formulas should be able to be copied down. The values it will be looking for in the 2nd position will be from 2 to 67. Thanks for any help.

mm combinations.xlsm
XYZAAAB
111, 2, 3, 4, 5ValueStart RowEnd Row
2501161, 2, 68, 69, 702150116
3501171, 3, 4, 5, 635011798021
4980211, 3, 68, 69, 70
Sheet2
 

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please update your profile button to show what version of Excel you are using?
 
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will the look for numbers ever repeat in the same cell?
 
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okay. can there be helper columns? With 2013 there is no way I know of that can treat the contents of a cell like an array.
It can be done with VBA probably, but I am not experienced in that.
 
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Here is a link where I used sumproduct for the 1 digit. I've tried adjusting it to count the 2nd digit but it gives wrong results.

 
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i'm not sure sumproduct works on values separated by commas to treat them as numeric. Can you use helper columns?
 
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How about in AA2
Excel Formula:
=INDEX(X:X,AGGREGATE(15,6,ROW($X$1:$X$4)/(REPLACE(MID($Y$1:$Y$4,1,FIND(",",$Y$1:$Y$4,4)-1),1,FIND(" ",$Y$1:$Y$4),"")=Z2&""),1))
and in AB2
Excel Formula:
=INDEX(X:X,AGGREGATE(14,6,ROW($X$1:$X$4)/(REPLACE(MID($Y$1:$Y$4,1,FIND(",",$Y$1:$Y$4,4)-1),1,FIND(" ",$Y$1:$Y$4),"")=Z2&""),1))
 
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