find the 1st break, 2nd break, and lunch from each date and each employee

uwmarkyo

New Member
Joined
Aug 11, 2021
Messages
44
Office Version
  1. 365
Platform
  1. Windows
hi I have a table as below:
I would like to create a column and find 1st break, 2nd break, and lunch.
1691008235603.png


if an agent on the same day, the aux name is Break and Duration is larger than 600. the first break will be the Break1, the second break will be the Break2.
if an agent on the same day, the aux name is Lunch and Duration is larger than 1000, it will be Lunch.

How do I perform this in Power BI DAX? I try couple time but it didn't work.
first Break =
VAR EmployeeDateBreaks =
FILTER(
'Adherence and Deviation',
[Employee Name] = EARLIER([Employee Name]) &&
[Date] = EARLIER([Date]) &&
[Aux Name] = "Break" &&
[Duration] > 600
)
RETURN
IF(
COUNTROWS(EmployeeDateBreaks) > 0 &&
RANKX(EmployeeDateBreaks, [Aux Start], , ASC) = 1,
"Break1",
BLANK()
)
Test.B1.ACTUAL =
VAR CurrentDate = 'Adherence and Deviation'[Date]
VAR CurrentEmployee = 'Adherence and Deviation'[Employee Name]
VAR FilteredTable = FILTER('Adherence and Deviation',[Date] = CurrentDate && [Employee Name] = CurrentEmployee &&
[Aux Name] = "break" &&
[Duration] >= 600)
VAR SecondBreakRow = ADDCOLUMNS ( FilteredTable, "Rank",
RANKX(FILTER('Adherence and Deviation', [Date] = CurrentDate &&
[Employee Name] = CurrentEmployee &&
[Aux Name] = "break" &&
[Duration] >= 600), [Aux Start], , ASC, Dense) )
RETURN IF ( NOT ISEMPTY(FilteredTable), MINX(FILTER(SecondBreakRow, [Rank] = 1), [Aux Start]), BLANK() )

Here is my dataset in table:
Table

thanks
 

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