Extracting a 7 number string from text

[walkinginheels24]

Hi,

I would like to find a macro that will extract a string a set of seven numbers from a string of text e.g.

WELDING COPPER WIRE PO: 6822835 5.0KG 0.8MM


Ideally, the macro will extract 6722835. However, the set of 7 numbers will not be in the same place in each string of text, nor will it be followed or preceded by the same qualitative data.

Thank you in advance.

 

[sandy666]

could you post more representative examples?

 

[JoeMo]

Here's a UDF you can try. Use it like a worksheet function as in the example below.

Excel Workbook
	A	B
1	WELDING COPPER WIRE PO: 6822835 5.0KG 0.8MM	6822835
Sheet3

Function SevenDigitNumber(S As String) As Double
Dim V As Variant
V = Split(S, " ")
For i = LBound(V) To UBound(V)
    If Val(V(i)) > 0 And Len(V(i)) = 7 Then
        SevenDigitNumber = Val(V(i))
        Exit Function
    End If
Next i
SevenDigitNumber = CVErr(xlErrValue)
End Function

To install the UDF:
1. With your workbook active press Alt and F11 keys. This will open the VBE window.
2. In the project tree on the left of the VBE window, find your project and click on it.
3. On the VBE menu: Insert>Module
4. Copy the UDF from your browser window and paste it into the white space in the VBE window.
5. Close the VBE window and Save the workbook. If you are using Excel 2007 or a later version do a SaveAs and save it as a macro-enabled workbook (.xlsm file extension).
6. Use the UDF as you would any native Excel function.
7. Make sure you have enabled macros whenever you open the file or the code will not run.

 

[lrobbo314]

Another UDF option.

Function SEVEN(s As String)
With CreateObject("VBScript.RegExp")
    .Pattern = "\d{7}"
    SEVEN = .Execute(s)(0)
End With
End Function

 

[Rick Rothstein]

Both of the above posted codes are not entirely robust. Joe's code will report incorrect values for things like 12.34e9, 12/3/45 and even &heeded... lrobbo314's code accepts any number with 7 or more digits, for example, 123456789.

It is always possible that I am wrong, but I believe this function to be fully robust...

Function GetSevenDigits(S As String) As Variant
  Dim X As Long
  For X = 1 To Len(S)
    If Mid(" " & S & " ", X, 9) Like "[!0-9]#######[!0-9]" Then
      GetSevenDigits = Mid(S, X, 7)
      Exit Function
    End If
  Next
  GetSevenDigits = ""
End Function

 

[Phuoc]

This formula does not work well:

=LOOKUP(10^8,MID(A1,ROW(INDIRECT("1:"&LEN(A1)-6)),7)
/ISERROR(--MID("x"&A1,ROW(INDIRECT("1:"&LEN(A1)-6)),1))
/ISERROR(--MID(A1&"x",ROW(INDIRECT("8:"&LEN(A1))),1)))

 

[Eric W]

Here's a formula that seems to work pretty well:

=MID(A1,MATCH(7,MMULT(--(ISNUMBER(MID(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),7),{1,2,3,4,5,6,7},1)+0)),{1;1;1;1;1;1;1}),0),7)
confirmed with Control+Shift+Enter.

About the only drawback I see with it is if there is an 8- (or more) digit number before the 7-digit number you want, it will pick up the first 7 digits of that number.

 

[Peter_SSs]

Another UDF (variation of post 4)

Function GetNum(S As String, Optional lngth As Long = 7) As String
  With CreateObject("VBScript.RegExp")
    .Pattern = "(\D|^)(\d{" & lngth & "})(\D|$)"
    If .Test(S) Then GetNum = .Execute(S)(0).SubMatches(1)
  End With
End Function

This one also has the option to search for a different number of consecutive digits by specifying a second argument, as shown in C1

Excel Workbook
	A	B	C
1	WELDING COPPER WIRE PO: 6822835 5.0KG 0.8MM 650M	6822835	650
Sheet2