FryGirl
Well-known Member
- Joined
- Nov 11, 2008
- Messages
- 1,366
- Office Version
- 365
- 2016
- Platform
- Windows
I know there has to be a more succinct solution than this. Any thoughts?
Data Range
[Table="class: grid"][tr][td] [/td][td]
[tr][td]
[tr][td]
[tr][td]
[tr][td]
[/table]
B2 copied down =MID(A2,FIND("@",SUBSTITUTE(A2,"/","@",LEN(A2)-LEN(SUBSTITUTE(A2,"/",""))))+1,LEN(A2))
Data Range
[Table="class: grid"][tr][td] [/td][td]
A
[/td][td]B
[/td][td]C
[/td][/tr][tr][td]
1
[/td][td]Path
[/td][td]
[/td][td]
[/td][/tr][tr][td]
2
[/td][td]sites/AF-DP-00-53/ManpowerStandards/AFMS/ManpowerGuides/AFMSs_Under_Study/Maintenance Overhead (non-LCOM)
[/td][td]Maintenance Overhead (non-LCOM)
[/td][td]6
[/td][/tr][tr][td]
3
[/td][td]sites/AF-DP-00-53/ManpowerStandards/AFMS/AirForceStandards/02-Alpha_Series
[/td][td]02-Alpha_Series
[/td][td]5
[/td][/tr][tr][td]
4
[/td][td]sites/AF-DP-00-53/ManpowerStandards/AFMS/ManpowerGuides
[/td][td]ManpowerGuides
[/td][td]4
[/td][/tr][/table]
B2 copied down =MID(A2,FIND("@",SUBSTITUTE(A2,"/","@",LEN(A2)-LEN(SUBSTITUTE(A2,"/",""))))+1,LEN(A2))