Extract all number of 6 digits in a string

Heremion

New Member
Joined
Nov 29, 2023
Messages
9
Office Version
  1. 365
Platform
  1. Windows
Hello everybody!

I'm a beginner in PowerQuery and I try to extract all numbers of 6 digits in a string for each of my records.

For example, following string I have :
497887;443445;#789788,112456,test;999877;john 788487

From this one, I'd like to extract the following value : 497887;443445;#789788,112456,;999877 788487

I'd like to include all separators (space, comma, etc...)

Could you help me please :(

Thanks a lot!
 

Excel Facts

Format cells as date
Select range and press Ctrl+Shift+3 to format cells as date. (Shift 3 is the # sign which sort of looks like a small calendar).
This probably isn't the easiest way, but assuming your column is called Column1, you could do:

Power Query:
Text.Remove(Text.Lower([Column1]),{"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"})
 
Upvote 1
@ExcelToDAX - I think it is the best way to keep the existing delimiters and symbols.
Perhaps a little shortcut for the letter list in your code.
Power Query:
Text.Remove(Text.Lower([Column1]),{"a".."z"})
 
Upvote 1
Solution
@ExcelToDAX - I think it is the best way to keep the existing delimiters and symbols.
Perhaps a little shortcut for the letter list in your code.
Power Query:
Text.Remove(Text.Lower([Column1]),{"a".."z"})
beautiful!! I knew there was some kind of shortcut :)
 
Upvote 0
Thanks for your answers! :) I completed your code with some others caracters to remove and its works fine!

Thanks a lot!
 
Upvote 0
Thanks for your answers! :) I completed your code with some others caracters to remove and its works fine!

Thanks a lot!
Good to hear it works @Heremion.
Can you tell us how you added other characters to remove them? I feel like the initial answer from @ExcelToDAX helped you better.

beautiful!! I knew there was some kind of shortcut :)
@ExcelToDAX - Actually, there is a recent trick about using Regex in PowerQuery that I have learned from @lrobbo314 here. Regex is really easy way of doing this. However, when I realized the delimiters and special chars should stay, I didn't post it. Still, as a reference, here is that solution for future readers.

Power Query:
let
    Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
    AddColumn = Table.TransformColumns(Source, 
        {"TextColumn", 
            (txt as text) =>
                let 
                    Matches = Web.Page("<script>document.write('" & txt & "'.match(/\d{6}/g))</script>"),
                    Numbers =  Matches{0}[Data]{0}[Children]{1}[Children]{0}[Text]
                            
                in
                    if Numbers = "null" then null else Numbers 
        }
    )
in
    AddColumn
Source and Result:
TextColumnTextColumn
497887;443445;#789788,112456,test;999877;john 788487497887,443445,789788,112456,999877,788487
497881;443445;#789788,112456,test;999877;john 788484497881,443445,789788,112456,999877,788484
497882;443445;#789788,112456,test;999877;john 788483497882,443445,789788,112456,999877,788483
49788;44345;#78988,11256,test;9877;john 78883
 
Upvote 0
A little modification to the Regular Expression as well as some Javascript to join the values in the array with a blank delimiter.

Book2
ABC
1TextColumnTextColumn
2497887;443445;#789788,112456,test;999877;john 788487497887;443445;789788,112456,;999877;788487
3497881;443445;#789788,112456,test;999877;john 788484497881;443445;789788,112456,;999877;788484
4497882;443445;#789788,112456,test;999877;john 788483497882;443445;789788,112456,;999877;788483
549788;44345;#78988,11256,test;9877;john 78883
Sheet1


Power Query:
let
    Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
    AddColumn = Table.TransformColumns(Source,
        {"TextColumn",
            (txt as text) =>
                let
                    Matches = Web.Page("<script>document.write('" & txt & "'.match(/(\d{6}|;|,)/g).join(''))</script>"),
                    Numbers =  Matches{0}[Data]{0}[Children]{1}[Children]{0}[Text]
                           
                in
                    if List.ContainsAny(Text.ToList(Numbers),{"0".."9"}) then Numbers else null
        }
    )
in
    AddColumn
 
Upvote 0
Nice touch, @lrobbo314!

Maybe a small Regex pattern change to avoid adjacent delimiters when the next item is not a 6-digits number:
Power Query:
let
    Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
    AddColumn = Table.TransformColumns(Source,
        {"TextColumn",
            (txt as text) =>
                let
                    Matches = Web.Page("<script>document.write('" & txt & "'.match(/(\d{6}[;,]?)/g).join(''))</script>"),
                    Found = Matches{0}[Data]{0},
                    Numbers = if Table.RowCount(Found[Children]) = 1 then "" else Found[Children]{1}[Children]{0}[Text]
                in
                    if List.ContainsAny(Text.ToList(Numbers),{"0".."9"}) then Numbers else null
        }
    )
in
    AddColumn

TextColumnTextColumn
497887;443445;#789788,112456,test;999877;john 788487497887;443445;789788,112456,999877;788487
497881;443445;#789788,112456,test;999877;john 788484497881;443445;789788,112456,999877;788484
497882;443445;#789788,112456,test;999877;john 788483497882;443445;789788,112456,999877;788483
49788;44345;#78988,11256,test;9877;john 78883

(I like the way you are using the List.ContainsAny() function by the way.)
 
Upvote 0
Thank you, sir. I dig the changes you made to the Regex.

Just because this was kind of fun, I did it with Python in Power BI as well.

Power Query:
let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMrE0t7AwtzYxMTYxMbVWNrcA8XUMDY1MTM10SlKLS6wtLS0tzM2ts/Iz8hSAciYW5kqxOlCNhiRpNEFoNCJJozFCI1gfRBtEF1wTshaQjlgA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [TextColumn = _t]),
    RunPython = Python.Execute("import pandas as pd#(lf)import re#(lf)dataset[""TextColumn""] = dataset['TextColumn'].apply(lambda x: ''.join(re.findall('(\d{6}[;,]?)',x))).apply(lambda x: x if bool(re.search(r'\d',x)) else None)",[dataset=Source])
in
    RunPython
 
Upvote 0

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