Extracrting string from cell - still getting error

[rangequestion]

Hi,

I have multiple rows where my cells look something like this: "+USD 17,286.24" or "-USD 40,918.66" . I just want to extract the number and I'm using this formula:
=RIGHT(F9,(FIND(" ",F9,1)-1))
which works on every other cell I have except where the format reads like my examples above.

Any ideas?

 

[Joe4]

Maybe this?

=RIGHT(F9,LEN(F9)-(FIND(" ",F9,1)))

 

[rangequestion]

Nope, still getting the value error

 

[Joe4]

I do not.
Where exactly are you getting this data from?
I suspect maybe the web or another program, and you are dealing with some special characters that are messing things up for you.
What does it say the length of those entries is, i.e.

=LEN(F9)

 

[rangequestion]

14. so that formula works

 

[rangequestion]

and yes, the data is being extracted form a web based program

 

[Rick Rothstein]

Nope, still getting the value error

What about this formula...

=REPLACE(F9,1,FIND(" ",F9),"")

 

[Fluff]

What does this return?
=FIND(" ",F9)

 

[rangequestion]

Nothing...argh.... Sample data below pasted directly from spreadsheet

[TABLE="width: 221"]
<tbody>[TR]
[TD]+USD 17,286.24[/TD]
[/TR]
[TR]
[TD]+USD 40,918.66[/TD]
[/TR]
[TR]
[TD]+USD 1,938,014.40[/TD]
[/TR]
[TR]
[TD]+USD 26,025.08[/TD]
[/TR]
[TR]
[TD]+USD 1,284.98[/TD]
[/TR]
</tbody><colgroup><col></colgroup>[/TABLE]

 

[Joe4]

What does this return?

=CODE(MID(F9,5,1))

Edit: checking the for same things that Fluff is. The fact that your answer to him is "nothing", that means you are not dealing with normal spaces here (so you cannot find one).

The code I gave you above will tell you what are dealing with, as it will return the ASCII code of the character in that place.