Excel VBA Help

M_S

New Member
Joined
Aug 6, 2021
Messages
14
Office Version
  1. 365
Platform
  1. Windows
Hello Everyone,

I need some help with the data below. So, I'm trying to assign numbers to the Values in Column B. For example ,if Column B has Apple in it and I assign it 22, I want the next item on the list to be 23 and so on. Same items should have same value, as you can see in Column A.

How can I achieve this using VBA? Any help would be much appreciated! Thanks!

Column AColumn B
22Apple
22Apple
22Apple
23Banana
23Banana
22Apple
23Banana
24Orange
24Orange
23Banana
22Apple
 

Excel Facts

Which lookup functions find a value equal or greater than the lookup value?
MATCH uses -1 to find larger value (lookup table must be sorted ZA). XLOOKUP uses 1 to find values greater and does not need to be sorted.
Does it need to be in VBA - you can accomplish the same goal with a formula - as below...

Book1
AB
1Column AColumn B
222apple
322apple
422apple
523banana
623banana
722apple
823banana
924orange
1024orange
1123banana
1222apple
1325watermelon
1422apple
1523banana
1623banana
1725watermelon
1826strawberry
1927raspberries
2025watermelon
2126strawberry
2222apple
2322apple
2423orange
2524orange
Sheet1
Cell Formulas
RangeFormula
A3:A25A3=IF(COUNTIF($B$2:$B2,B3)>0,INDEX($A$2:$B2,MATCH(B3,$B$2:$B2),1),MAX($A$2:$A2)+1)


It may not be a particularly elegant formula, and it requires a starting number for the first item (see A2 = 22), but other than that it seems to work.
 
Upvote 0
Does it need to be in VBA - you can accomplish the same goal with a formula - as below...

Book1
AB
1Column AColumn B
222apple
322apple
422apple
523banana
623banana
722apple
823banana
924orange
1024orange
1123banana
1222apple
1325watermelon
1422apple
1523banana
1623banana
1725watermelon
1826strawberry
1927raspberries
2025watermelon
2126strawberry
2222apple
2322apple
2423orange
2524orange
Sheet1
Cell Formulas
RangeFormula
A3:A25A3=IF(COUNTIF($B$2:$B2,B3)>0,INDEX($A$2:$B2,MATCH(B3,$B$2:$B2),1),MAX($A$2:$A2)+1)


It may not be a particularly elegant formula, and it requires a starting number for the first item (see A2 = 22), but other than that it seems to work.
Thank you, Dan. Yes, I was actually looking for something in VBA.

Thanks for you help tho, appreciate it!
 
Upvote 0
Curious - what do you need it for? I may be able to help if you can give some more information.
 
Upvote 0
How about
VBA Code:
Sub M_S()
   Dim Cl As Range
   Dim StartNo As Variant
   
   StartNo = InputBox("Please enter a start number")
   If StartNo = "" Then Exit Sub
   With CreateObject("scripting.dictionary")
      For Each Cl In Range("B2", Range("B" & Rows.Count).End(xlUp))
         If Not .Exists(Cl.Value) Then .Add Cl.Value, StartNo + .Count
         Cl.Offset(, -1).Value = .Item(Cl.Value)
      Next Cl
   End With
End Sub
 
Upvote 0
How about
VBA Code:
Sub M_S()
   Dim Cl As Range
   Dim StartNo As Variant
  
   StartNo = InputBox("Please enter a start number")
   If StartNo = "" Then Exit Sub
   With CreateObject("scripting.dictionary")
      For Each Cl In Range("B2", Range("B" & Rows.Count).End(xlUp))
         If Not .Exists(Cl.Value) Then .Add Cl.Value, StartNo + .Count
         Cl.Offset(, -1).Value = .Item(Cl.Value)
      Next Cl
   End With
End Sub
Thank you so much! It worked like Magic, you're awesome!
Is it possible, if there's another column "C" and I want to match if it falls in the same category. So, everything in Bucket 1 will have a series and then Bucket 2 will have continuation of the series, regardless if column B has same value?


Column AColumn BColumn C
1AppleBucket 1
1AppleBucket 1
2BananaBucket 1
3OrangeBucket 1
4OrangeBucket 2
5AppleBucket 2
5AppleBucket 2
6BananaBucket 3
7AppleBucket 3
8OrangeBucket 4
8OrangeBucket 4
9AppleBucket 4
10BananaBucket 4
 
Upvote 0
How about
VBA Code:
Sub M_S()
   Dim Cl As Range
   Dim StartNo As Variant
   
   StartNo = InputBox("Please enter a start number")
   If StartNo = "" Then Exit Sub
   With CreateObject("scripting.dictionary")
      For Each Cl In Range("B2", Range("B" & Rows.Count).End(xlUp))
         If Not .Exists(Cl.Value & "|" & Cl.Offset(, 1).Value) Then .Add Cl.Value & "|" & Cl.Offset(, 1).Value, StartNo + .Count
         Cl.Offset(, -1).Value = .Item(Cl.Value & "|" & Cl.Offset(, 1).Value)
      Next Cl
   End With
End Sub
 
Upvote 0
Solution
How about
VBA Code:
Sub M_S()
   Dim Cl As Range
   Dim StartNo As Variant
  
   StartNo = InputBox("Please enter a start number")
   If StartNo = "" Then Exit Sub
   With CreateObject("scripting.dictionary")
      For Each Cl In Range("B2", Range("B" & Rows.Count).End(xlUp))
         If Not .Exists(Cl.Value & "|" & Cl.Offset(, 1).Value) Then .Add Cl.Value & "|" & Cl.Offset(, 1).Value, StartNo + .Count
         Cl.Offset(, -1).Value = .Item(Cl.Value & "|" & Cl.Offset(, 1).Value)
      Next Cl
   End With
End Sub
This didn't work. Does it have anything to do with "|"?
 
Upvote 0
It actually did work! Thanks a heap! I'm out of words.
Is there a way to apply this formula to only visible cells? I have a filter on in another column but for some reason it gets applied to hidden cells as well.
 
Upvote 0

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