Spencer0202
New Member
- Joined
- Mar 23, 2022
- Messages
- 2
- Office Version
- 365
- Platform
- Windows
I am trying to create a schedule in excel that will account for fractions of a day.
Column H is the task duration - Column I are my start dates - Column J are my end dates
task #1 takes .5 a day (.5 in cell H1) - start date is set at 4/18/22 (4/18/22 in cell I1) - What formula works for J1 so it ends up showing 4/18/22 but still accounting for half the day?
task #2 takes 2.75 days (2.75 in H2) - if I put (=J1) in cell I2 it just puts the start time for task #2 at the beginning of 4/18/22. It does not account for the .5 day from task #1. what formula works for I2 to incorporate the time spent on the previous task?
task #3 takes .75 days (.75 in H3) - J3 start date should be 4/21 because task 1 and 2 are 3.25 days so 18th is day 1, 19th is day 2, 20th is day 3. The .75 from task #3 means task #3 should end at the end of the day on 4/21, which is the 4th day from 4/18. And then task #5 would start at the beginning of 4/22/22
Not sure if it would help converting everything into hours and then count on a 10 hour work day so .1=1hr , .5=5 hours(half a day), ect. But we typically work 4-10hour shifts. I am factoring my TASK DURATION in days and fractions of days so I do not care about start time of working hours during the day (unless that needs to come into play for the formula someone provides, it does not matter to me)
I have been wasting so much time scouring these threads and trying to watch video playing with the workday, workdayint function. I saw one thread they were trying to calculate it as a SUM function but everything I have seen or tried has not worked and would not account for the fraction of the day before.
Any help on this would be extremely appreciated.
Thank you, Spencer
Column H is the task duration - Column I are my start dates - Column J are my end dates
task #1 takes .5 a day (.5 in cell H1) - start date is set at 4/18/22 (4/18/22 in cell I1) - What formula works for J1 so it ends up showing 4/18/22 but still accounting for half the day?
task #2 takes 2.75 days (2.75 in H2) - if I put (=J1) in cell I2 it just puts the start time for task #2 at the beginning of 4/18/22. It does not account for the .5 day from task #1. what formula works for I2 to incorporate the time spent on the previous task?
task #3 takes .75 days (.75 in H3) - J3 start date should be 4/21 because task 1 and 2 are 3.25 days so 18th is day 1, 19th is day 2, 20th is day 3. The .75 from task #3 means task #3 should end at the end of the day on 4/21, which is the 4th day from 4/18. And then task #5 would start at the beginning of 4/22/22
Not sure if it would help converting everything into hours and then count on a 10 hour work day so .1=1hr , .5=5 hours(half a day), ect. But we typically work 4-10hour shifts. I am factoring my TASK DURATION in days and fractions of days so I do not care about start time of working hours during the day (unless that needs to come into play for the formula someone provides, it does not matter to me)
I have been wasting so much time scouring these threads and trying to watch video playing with the workday, workdayint function. I saw one thread they were trying to calculate it as a SUM function but everything I have seen or tried has not worked and would not account for the fraction of the day before.
Any help on this would be extremely appreciated.
Thank you, Spencer