Excel Function or VBA to validate each character in cell to match various input masks

G

GREGO99

New Member
Joined
Mar 28, 2022
Messages
4
Office Version
  1. 365
Platform
  1. Windows
for example >LLLL-99-99-99-LLL9999-LL## where L is ALPHA, 9 numeric, # can be either.

example of cell passing this mask; "ABCD-10-20-45-ABC1234-AB00"

a function would be best the have a column to flag the data column good/bad and perhaps where "bad"

thanks for any guidance,

Greg

SAMPLE.xlsx
AB
1DATAGOOD/BAD
2ABCD-10-20-45-ABC1234-AB00G
3ABCD-10-20-45-ABC1234-AB01G
4ABCD-10-20-45-ABC12B4-AB02B
5ABCD-10-20-45-ABC1234-A123B
6ABCD-10-20-45-ABC1234-AB04G
7ABCD-10-20-45-ABC1234-AB05G
8ABCD-10-20-45-ABC1234-1234B
9ABCD-10-20-45-ABC1234-AB07G
Sheet1


1648504405856.png
 

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Blank_2_Years (25).xlsx
ABC
1DATAGOOD/BADREGEX
2ABCD-10-20-45-ABC1234-AB00GG
3ABCD-10-20-45-ABC1234-AB01GG
4ABCD-10-20-45-ABC12B4-AB02BB
5ABCD-10-20-45-ABC1234-A123BB
6ABCD-10-20-45-ABC1234-AB04GG
7ABCD-10-20-45-ABC1234-AB05GG
8ABCD-10-20-45-ABC1234-1234BB
9ABCD-10-20-45-ABC1234-AB07GG
Sheet3
Cell Formulas
RangeFormula
C2:C9C2=ISVALID(A2)


VBA Code: 
Function ISVALID(s As String)
With CreateObject("VBScript.RegExp")
    .Global = True
    .Pattern = "\D{4}(?:-\d{2}){3}-\D{3}\d{4}-\D{2}\w{2}"
    ISVALID = IIf(.test(s), "G", "B")
End With
End Function
 
Last edited:
Upvote 0
Here is a direct Excel formula that will also work...
Excel Formula: 
=IF(AND(LEN(A2)=26,AND(MID(A2,{5,8,11,14,22},1)="-"),IF(MID("AAAA-00-00-00-AAA0000-AA00",{1,2,3,4,6,7,9,10,12,13,15,16,17,18,19,20,21,23,24,25,26},1)="A",(MID(A2,{1,2,3,4,6,7,9,10,12,13,15,16,17,18,19,20,21,23,24,25,26},1)>="A")*(MID(A2,{1,2,3,4,6,7,9,10,12,13,15,16,17,18,19,20,21,23,24,25,26},1)<="Z"),ISNUMBER(-MID(A2,{1,2,3,4,6,7,9,10,12,13,15,16,17,18,19,20,21,23,24,25,26},1)))),"G","B")
 
Upvote 0
lrobbo314 said:
Blank_2_Years (25).xlsx
ABC
1DATAGOOD/BADREGEX
2ABCD-10-20-45-ABC1234-AB00GG
3ABCD-10-20-45-ABC1234-AB01GG
4ABCD-10-20-45-ABC12B4-AB02BB
5ABCD-10-20-45-ABC1234-A123BB
6ABCD-10-20-45-ABC1234-AB04GG
7ABCD-10-20-45-ABC1234-AB05GG
8ABCD-10-20-45-ABC1234-1234BB
9ABCD-10-20-45-ABC1234-AB07GG
Sheet3
Cell Formulas
RangeFormula
C2:C9C2=ISVALID(A2)


VBA Code: 
Function ISVALID(s As String)
With CreateObject("VBScript.RegExp")
    .Global = True
    .Pattern = "\D{4}(?:-\d{2}){3}-\D{3}\d{4}-\D{2}\w{2}"
    ISVALID = IIf(.test(s), "G", "B")
End With
End Function
Click to expand...
Thank-you, that is elegant and works perfectly on sample data I provided. However, I realized it wont work if I have "shorter" valid data; (also I have questions on the code, and assumptions)

SAMPLE.xlsm
ABCDEFGHIJKLM
1DATAGOOD/BADTESTPattern = "\D{4}(?:-\d{2}){3}-\D{3}\d{4}-\D{2}\w{2}"Function ISVALID(s As String)
2ABCD-10-20-45-ABC1234-AB00GGWith CreateObject("VBScript.RegExp")
3ABCD-10-20-45-ABC1234-AB01GGD = alpha4 1st chars .Global = True
4ABCD-10-20-45-ABC12B4-AB02BB?:means what? .Pattern = "\D{4}(?:-\d{2}){3}-\D{3}\d{4}-\D{2}\w{2}"
5ABCD-10-20-45-ABC1234-A123BB-means must be dash ISVALID = IIf(.test(s), "G", "B")
6ABCD-10-20-45-ABC1234-AB04GG\d= numericdash then next 2 chars, repeat 3 timesEnd With
7ABCD-10-20-45-ABC1234-AB05GG-means must be dashEnd Function
8ABCD-10-20-45-ABC1234-1234BB\D = alphanext 3 chars
9ABCD-10-20-45-ABC1234-AB07GG\dnext 4 are numeric
10ABCD-10-20-45-ABC1234GB-means must be dash
11ABCD-10GB\D = alphanext 2 alpha
12\w= alpha or numeric ?
13
14HOW TO MAKE IT ALLOW SHORTER DATA ?
Sheet1
Cell Formulas
RangeFormula
C2:C11C2=ISVALID(A2)
 
Upvote 0
Give this UDF a try...
VBA Code: 
Function IsValid(S As String) As String
  Dim Pattern As String
  Pattern = Replace(Replace(Left("LLLL-##-##-##-LLL####-LLAA", Len(S)), "A", "[0-9A-Z]"), "L", "[A-Z]")
  IsValid = Mid("BG", 1 + (S Like Pattern) * (Len(S) > 6), 1)
End Function
Note: This function assumes the minimum length of an entry must be 7 characters (4 letters, 1 dash, 2 digits).
 
Upvote 0
Solution
Rick Rothstein said:
Give this UDF a try...
VBA Code: 
Function IsValid(S As String) As String
  Dim Pattern As String
  Pattern = Replace(Replace(Left("LLLL-##-##-##-LLL####-LLAA", Len(S)), "A", "[0-9A-Z]"), "L", "[A-Z]")
  IsValid = Mid("BG", 1 + (S Like Pattern) * (Len(S) > 6), 1)
End Function
Note: This function assumes the minimum length of an entry must be 7 characters (4 letters, 1 dash, 2 digits).
Click to expand...
Very cool solution, thanks! I think I can figure the logic to apply to other patterns.
 
Upvote 0
Inspired by Rick's worksheet formula attempt at the original question, I thought I would try for one here.
Also, since I'm keen to practice regular expressions I have suggested another udf.
Both suggestions I think should work for any shortening of the original pattern.

VBA Code: 
Function GB(S As String) As String
  Dim RX As Object
  
  Const Pat As String = "LLLLHDDHDDHDDHLLLDDDDHLLXX" 'L=Letter, H = Hyphen, D = Digit, X = Letter or Digit
  Set RX = CreateObject("VBScript.RegExp")
  RX.Pattern = "^" & Replace(Replace(Replace(Replace(Left(Pat, Len(S)), "L", "[A-Z]"), "H", "\-"), "D", "\d"), "X", "[A-Z\d]") & "$"
  If Len(S) > 0 Then GB = Mid("BG", 1 - RX.Test(S), 1)
End Function

GREGO99.xlsm
ACD
1DATATESTTEST
2ABCD-10-20-45-ABC1234-AB00GG
3ABCD-10-20-45-ABC1234-AB01GG
4ABCD-10-20-45-ABC12B4-AB02BB
5ABCD-10-20-45-ABC1234-A123BB
6ABCD-10-20-45-ABC1234-AB04GG
7ABCD-10-20-45-ABC1234-AB05GG
8ABCD-10-20-45-ABC1234-1234BB
9ABCD-10-20-45-ABC1234-AB07GG
10ABCD-10-20-45-ABC1234GG
11ABCD-10GG
12  
13AGG
14WXYZ-GG
158BB
16ABCD-10-20-45-ABC1234-ABXXGG
Sheet1
Cell Formulas
RangeFormula
C2:C16C2=LET(s,A2,D,CONCAT(MID(s,{5,8,11,14,22},1)),L,MID(s,1,4)&MID(s,15,3)&MID(s,23,2),N,CONCAT(MID(s,{6,9,12,18,20},2)),y,MID(s,25,1),z,MID(s,26,1),aa,SUBSTITUTE(D,"-","")="",bb,ABS(77.5-CODE(MID(L,SEQUENCE(LEN(L)),1)))<13,cc,IF(LEN(N)=0,TRUE,ISNUMBER(-MID(N,SEQUENCE(LEN(N)),1))),dd,AND(OR(ISNUMBER(y+0),ABS(77.7-CODE(y&"A"))<13),OR(ISNUMBER(z+0),ABS(77.7-CODE(z&"A"))<13)),IF(LEN(s)=0,"",IF(AND(aa,bb,cc,dd),"G","B")))
D2:D16D2=GB(A2)
 
Upvote 0
Peter_SSs said:
Inspired by Rick's worksheet formula attempt at the original question, I thought I would try for one here.
Also, since I'm keen to practice regular expressions I have suggested another udf.
Both suggestions I think should work for any shortening of the original pattern.

VBA Code: 
Function GB(S As String) As String
  Dim RX As Object
 
  Const Pat As String = "LLLLHDDHDDHDDHLLLDDDDHLLXX" 'L=Letter, H = Hyphen, D = Digit, X = Letter or Digit
  Set RX = CreateObject("VBScript.RegExp")
  RX.Pattern = "^" & Replace(Replace(Replace(Replace(Left(Pat, Len(S)), "L", "[A-Z]"), "H", "\-"), "D", "\d"), "X", "[A-Z\d]") & "$"
  If Len(S) > 0 Then GB = Mid("BG", 1 - RX.Test(S), 1)
End Function

GREGO99.xlsm
ACD
1DATATESTTEST
2ABCD-10-20-45-ABC1234-AB00GG
3ABCD-10-20-45-ABC1234-AB01GG
4ABCD-10-20-45-ABC12B4-AB02BB
5ABCD-10-20-45-ABC1234-A123BB
6ABCD-10-20-45-ABC1234-AB04GG
7ABCD-10-20-45-ABC1234-AB05GG
8ABCD-10-20-45-ABC1234-1234BB
9ABCD-10-20-45-ABC1234-AB07GG
10ABCD-10-20-45-ABC1234GG
11ABCD-10GG
12  
13AGG
14WXYZ-GG
158BB
16ABCD-10-20-45-ABC1234-ABXXGG
Sheet1
Cell Formulas
RangeFormula
C2:C16C2=LET(s,A2,D,CONCAT(MID(s,{5,8,11,14,22},1)),L,MID(s,1,4)&MID(s,15,3)&MID(s,23,2),N,CONCAT(MID(s,{6,9,12,18,20},2)),y,MID(s,25,1),z,MID(s,26,1),aa,SUBSTITUTE(D,"-","")="",bb,ABS(77.5-CODE(MID(L,SEQUENCE(LEN(L)),1)))<13,cc,IF(LEN(N)=0,TRUE,ISNUMBER(-MID(N,SEQUENCE(LEN(N)),1))),dd,AND(OR(ISNUMBER(y+0),ABS(77.7-CODE(y&"A"))<13),OR(ISNUMBER(z+0),ABS(77.7-CODE(z&"A"))<13)),IF(LEN(s)=0,"",IF(AND(aa,bb,cc,dd),"G","B")))
D2:D16D2=GB(A2)
Click to expand...
Thanks! a great solution!
 
Upvote 0
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