Excel 2016 & 2021 VBA trying to open workbook based on Sheet 7 cell D3

CrashOD

Board Regular
Joined
Feb 5, 2019
Messages
118
Office Version
  1. 2021
  2. 2016
Platform
  1. Windows
' To load work book based on cell value
' Real Estate Books
Dim varCellvalueReal As String
'Filename:=Sheets("Sheet1").Range("A2").Value & "\" & Sheets("Sheet2").Range("A2").Value)
varCellvalueReal = Workbook(Filename:=Sheets("Sheet7").Range("D3").Value) ' & "\" & Sheets("Sheet2").Range("A2").Value)
' Personal Books
'Dim varCellvaluePer As String
varCellvaluePer = Range.Worksheet(7, ("D3"))




strFromDate = txtFromDate.Value
strToDate = txtToDate.Value

aFromDate = Split(strFromDate, "/")
aToDate = Split(strToDate, "/")

dtFromDate = DateSerial(aFromDate(2), aFromDate(0), aFromDate(1))
dtToDate = DateSerial(aToDate(2), aToDate(0), aToDate(1))
dtCheckDate = dtFromDate

Application.Interactive = False

Set oReportWorkbook = ActiveWorkbook
Set oReportWorksheet = ActiveSheet

' To Open WOrkbooks
Set oWorkbook1 = Workbooks.Open(varCellvaluePer)
Set oWorkbook2 = Workbooks.Open(varCellvalueReal)



Sheet7
ECT - Report_V1_3-1-test.xlsm
ABCDEFG
1LocationFileJoined
2RealD:\Country&LocalReport\2022 - ECT - Real Estate.xlsxD:\Country&LocalReport\2022 - ECT - Real Estate.xlsx
3PersonalD:\Country&LocalReport\2022 - ECT - C&L - Personal.xlsmD:\Country&LocalReport\2022 - ECT - C&L - Personal.xlsm
4Rows7000
Report Location
Cell Formulas
RangeFormula
D2:D3D2=CONCATENATE(B2,C2)
 

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had my answer but thanks !
 
Upvote 0
' To load work book based on cell value
' Real Estate Books
varCellvalueReal = Trim(LTrim(Cells(2, "D").Value)) '1 is rownumber A is the column, read address from A1
' Personal Books
'Dim varCellvaluePer As String
'varCellvaluePer = Range.Worksheet(7, ("D3"))
varCellvaluePer = Trim(LTrim(Cells(3, "D").Value)) '1 is rownumber A is the column, read address from A1

lol so messed up. how do i get it to read from Sheet7 cell D2
 
Upvote 0

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