Error when using Index Match formula

Preacherman771

New Member
Joined
Jun 15, 2021
Messages
46
Office Version
  1. 365
Platform
  1. Windows
I am stumped when using an INDEX MATCH formula which I have used many times. I am trying to find the value of two given items, "2" & "Bal". When using =INDEX($AA$8:$AP$8,MATCH(1,(AD$15=$AA$7:$AP$7)*($Z8=$Z$7:$Z$14),0)), as I have always, I receive "N/A" as the result. I would appreciate a fresh set of eyes to find what I am missing and/or writing wrong. I intend to once corrected, to include IFERROR in order to catch the blank cells.

Cell Formulas
RangeFormula
AA7AA7=IF(T7<>T6,FILTER($R$7:$R$22,$T$7:$T$22=$T7),"")
AB7AB7=IF(T8<>T7,FILTER($R$7:$R$22,$T$7:$T$22=$T8),"")
AC7AC7=IF(T9<>T8,FILTER($R$7:$R$22,$T$7:$T$22=$T9),"")
AD7:AD10AD7=IF(T10<>T9,FILTER($R$7:$R$22,$T$7:$T$22=$T10),"")
AE7AE7=IF(T11<>T10,FILTER($R$7:$R$22,$T$7:$T$22=$T11),"")
AF7AF7=IF(T12<>T11,FILTER($R$7:$R$22,$T$7:$T$22=$T12),"")
AG7AG7=IF(T13<>T12,FILTER($R$7:$R$22,$T$7:$T$22=$T13),"")
AH7AH7=IF(T14<>T13,FILTER($R$7:$R$22,$T$7:$T$22=$T14),"")
AI7AI7=IF(T15<>T16,FILTER($R$7:$R$22,$T$7:$T$22=$T15),"")
AJ7:AJ8AJ7=IF(T16<>T15,FILTER($R$7:$R$22,$T$7:$T$22=$T16),"")
AK7AK7=IF(T17<>T16,FILTER($R$7:$R$22,$T$7:$T$22=$T17),"")
AL7AL7=IF(T18<>T17,FILTER($R$7:$R$22,$T$7:$T$22=$T18),"")
AM7AM7=IF(T19<>T18,FILTER($R$7:$R$22,$T$7:$T$22=$T19),"")
AN7AN7=IF(T20<>T19,FILTER($R$7:$R$22,$T$7:$T$22=$T20),"")
AO7AO7=IF(T21<>T20,FILTER($R$7:$R$22,$T$7:$T$22=$T21),"")
AP7AP7=IF(T22<>T21,FILTER($R$7:$R$22,$T$7:$T$22=$T22),"")
AA15:AP15AA15=IF(COLUMNS($AA$15:AA15)+COUNTIF($AA$7:AA7,"")>=17,"", IF(AA$7<>"",(IF(COUNTIF($Z$15:Z15,AA$7)<>1,AA$7,INDEX($AA$7:$AP$7,SMALL(IF($AA$7:$AP$7<>"",COLUMN($AA$7:$AP$7)-COLUMN($AA$7)+1),AA6)))), INDEX($AA$7:$AP$7,SMALL(IF($AA$7:$AP$7<>"",COLUMN($AA$7:$AP$7)-COLUMN($AA$7)+1),AA6))))
AA16:AL22AA16=INDEX($AA$8:$AP$8,MATCH(1,(AA$15=$AA$7:$AP$7)*($Z8=$Z$7:$Z$14),0))
Dynamic array formulas.
 

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Not entirely sure, what you are tring to do with that formula, but does this do what you want.
Excel Formula:
=INDEX($AA$8:$AP$14,MATCH($Z8,$Z$8:$Z$14,0),MATCH(AA$15,$AA$7:$AP$7,0))
 
Upvote 0
Match only works with a 1 column/row range (or array). Your criteria is multiplying a vertical array by a horizontal one, which creates a 2 d array. It looks to me like you want a regular INDEX(..,MATCH(), MATCH) formula?
 
Upvote 0
Solution
Walked away and relooked at my situation and discovered the error. Since I'm indexing the row which is the value "2", I don't need to MATCH it. INDEX($AA$8:$AP$8,MATCH(AA$15,$AA$7:$AP$7,0)). Duh!!!
 
Upvote 0
Glad you sorted it & thanks for the feedback.
 
Upvote 0

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