Error message when executing macro

sofas

Well-known Member
Joined
Sep 11, 2022
Messages
559
Office Version
  1. 2021
  2. 2019
Platform
  1. Windows
Hi I am trying to convert formulas to vba code but I am facing an error in the next row I do not know how I can correct it

VBA Code:
Sub Macro3()


Dim lr As Long
Dim sh As Worksheet: Set sh = Sheets("Source")
Dim dest As Worksheet: Set dest = Sheets("Dest")

lr = sh.Cells(Rows.Count, 1).End(xlUp).Row
 
 ws1 = sh.Name: WS2 = dest.Name

Set a = sh.Range("A2:A" & lr): Set b = sh.Range("B2:B" & lr)
Set c = sh.Range("C2:C" & lr): Set d = sh.Range("D2:D" & lr)

With dest.Range("b2:b" & Range("a" & Rows.Count).End(3).Row)
.Formula = "=IFERROR(INDEX('" & ws1 & "'!" & c.Address & "," & "MATCH(""=""&$E$1,'" & ws1 & "'!" & a.Address & ",""=""&$a$2,'" & ws1 & "'!" & b.Address

'.Formula = =IFERROR(INDEX(Source!$C$2:C$100; MATCH(1;($E$1=Source!A$2:A$100)*(A2=Source!B$2:B$100); 0));"")
   
With dest.Range("c2:c" & Range("a" & Rows.Count).End(3).Row)
.Formula = "=SUMIFS('" & ws1 & "'!" & d.Address & ",'" & ws1 & "'!" & a.Address & ",""=""&$E$1,'" & ws1 & "'!" & c.Address & ",""=""&$B2,'" & ws1 & "'!" & b.Address & ",A2)"
' Formula = "=SUMIFS('Source'!$D$2:D$100,'Source'!$A$2:A$100,$E$1,'Source'!$C$2:C$100,b2,'Source'!$B$2:B$100,a2)"
   
'         .Value = .Value
'         .Value = .Value


    End With
    End With
End Sub
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I am facing an error
Excel has many errors. It is better to always include information about the error number and error message.

The formula produced by this line of code
VBA Code:
.Formula = "=IFERROR(INDEX('" & ws1 & "'!" & c.Address & "," & "MATCH(""=""&$E$1,'" & ws1 & "'!" & a.Address & ",""=""&$a$2,'" & ws1 & "'!" & b.Address

Does not match the reference formula you have included here:
VBA Code:
'.Formula = =IFERROR(INDEX(Source!$C$2:C$100; MATCH(1;($E$1=Source!A$2:A$100)*(A2=Source!B$2:B$100); 0));"")

So I'm guessing that the error had something do do with that. Instead of assigning the formula directly to the range .Formula property as you are doing here:
VBA Code:
.Formula = "=IFERROR(INDEX('" & ws1 & "'!" & c.Address & "," & "MATCH(""=""&$E$1,'" & ws1 & "'!" & a.Address & ",""=""&$a$2,'" & ws1 & "'!" & b.Address

Use a variable (FormulaStr) to create the formula first:
VBA Code:
Dim FormulaStr As String
With dest.Range("b2:b" & Range("a" & Rows.Count).End(3).Row)
'.Formula = "=IFERROR(INDEX('" & ws1 & "'!" & c.Address & "," & "MATCH(""=""&$E$1,'" & ws1 & "'!" & a.Address & ",""=""&$a$2,'" & ws1 & "'!" & b.Address
FormulaStr = "=IFERROR(INDEX('" & ws1 & "'!" & c.Address & "," & "MATCH(""=""&$E$1,'" & ws1 & "'!" & a.Address & ",""=""&$a$2,'" & ws1 & "'!" & b.Address

Debug.Print FormulaStr  '<--- to inspect the formula in the VBE Immediate window.
End                     '<---- temporary, to be removed after you get the formula fixed

.Formula = FormulaStr

That way you can inspect the formula, compare it to your reference formula and make adjustments as needed until you get it right.
 
Upvote 0
VBA Code:
Sub Macro3()

Dim lr As Long, lige As Long
Dim sh As Worksheet: Set sh = Sheets("Source")
Dim dest As Worksheet: Set dest = Sheets("Dest")

lr = sh.Cells(Rows.Count, 1).End(xlUp).Row
     lige = dest.Cells(Rows.Count, 1).End(xlUp).Row

 ws1 = sh.Name: WS2 = dest.Name

Set a = sh.Range("A2:A" & lr): Set b = sh.Range("B2:B" & lr)
Set c = sh.Range("C2:C" & lr): Set d = sh.Range("D2:D" & lr)

Application.ScreenUpdating = False
    Dim i As Long
    For i = 2 To lige
  
        dest.Cells(i, "B") = Evaluate( _
            "=IFERROR(INDEX('Source'!$C:$C,MATCH(" _
            & dest.Cells(i, "A").Address _
            & ",'Source'!$B:$B,0),1),"""")")
                
[B]'Formula = "=IFERROR(INDEX('Source'!$C$2:C$100, MATCH(1,($E$1='Source'!A$2:A$100)*(a2='Source'!B$2:B$100), 0)),"""")"[/B]
Next
With dest.Range("c2:c" & Range("a" & Rows.Count).End(3).Row)
.Formula = "=SUMIFS('" & ws1 & "'!" & d.Address & ",'" & ws1 & "'!" & a.Address & ",""=""&$E$1,'" & ws1 & "'!" & c.Address & ",""=""&$B2,'" & ws1 & "'!" & b.Address & ",A2)"

         .Value = .Value


    End With
  
End Sub

I changed the code except the following figure. It works well, but I need to add another condition, which is to fetch the data provided that cell e1, as in the formula below, matches column A.

Formula = "=IFERROR(INDEX('Source'!$C$2:C$100, MATCH(1,($E$1='Source'!A$2:A$100)*(a2='Source'!B$2:B$100), 0)),"""")"
 
Upvote 0
That looks like the same formula you had before.
 
Upvote 0

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