Drag down formula in row an increment value by more than 1

jeffdlinn

New Member
Joined
Nov 18, 2013
Messages
29
Office Version
  1. 365
Platform
  1. Windows
I think I need the ROW function here, but I can't seem to get it to work.

In sheet 2 I reference values in Sheet 1 and when I drag down the formula it performs as expected.

Row 1 =Sheet1!A1
Row 2 =Sheet1!A2
Row 3 =Sheet1!A3
Row 4 =Sheet1!A4
Row 5 =Sheet1!A5
Row 6 =Sheet1!A6
When I drag the formula down I want it to increment by different values maybe 2, 5, 7,50. In this case, I need it to increment by 12. So when I drag the formula down it should be as follows.
Row 1 =Sheet1!A1
Row 2 =Sheet1!A12
Row 3 =Sheet1!A24
Row 4 =Sheet1!A36
Row 5 =Sheet1!A48
Row 6 =Sheet1!A60

Seems to be a simple request, but I can't figure out how to do this.
 

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Row 1 =Sheet1!A1
Row 2 =Sheet1!A12
Row 3 =Sheet1!A24
Row 4 =Sheet1!A36
Row 5 =Sheet1!A48
Row 6 =Sheet1!A60

If you're increment by 12 should it be 1,13,25, 37, etc....?
 
Upvote 0
In Sheet2!A1, you could have: =INDEX(Sheet1!A:A,ROWS(A$1:A1)*12-11), and copy down

Or with Excel 365, you could do it in the one formula:

=INDEX(Sheet1!A:A,SEQUENCE(6,,1,12))

Edit: Yes, I assumed: 1,13,25, 37, etc....? Adjust the formula as appropriate
 
Upvote 0
Assuming this is what you want... 1,12,24,36, ...
Keep Row 1 = Sheet1!A1
Paste this in Row 2 & drag down.
Excel Formula:
=OFFSET(Sheet1!$A$1,12*ROW(A2)-13,0)
 
Upvote 0
In Sheet2!A1, you could have: =INDEX(Sheet1!A:A,ROWS(A$1:A1)*12-11), and copy down

Or with Excel 365, you could do it in the one formula:

=INDEX(Sheet1!A:A,SEQUENCE(6,,1,12))

Edit: Yes, I assumed: 1,13,25, 37, etc....? Adjust the formula as appropriate


So close. I tried the first formula. See the spreadsheet above and see the Yearly tab Column O (Cell O12). The numbers I am expecting to see are in Column P
 
Upvote 0
You have O12: =INDEX(Amortization!F6:F642,ROWS(F$1:F1)*12-11)

Try O12: =INDEX(Amortization!F$17:F$642,ROWS(F$12:F12)*12-11)
 
Upvote 0
Solution

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