Difference between two values.

Romano_odK

Active Member
Joined
Jun 4, 2020
Messages
380
Office Version
  1. 365
Platform
  1. Windows
Good morning,
I can't figure out what I am doing wrong here. I want to know the difference in % between the cost price and the purchase price taking into account the factor I have. Usually I add 3% to the purchase price and that is what I like to see but what I get is 2,75 instead of the 3% I added. What am I doing wrong here?

Thank you for you time.

Romano

Artikelen beheren XML 5.01.xlsm
ABC
1Purchase priceCost priceFactor
274,402,5530
3
42,75%
Sheet2
Cell Formulas
RangeFormula
A4A4=(100%-(((A2/C2)/B2)))
 

Excel Facts

Show numbers in thousands?
Use a custom number format of #,##0,K. Each comma after the final 0 will divide the displayed number by another thousand
How did you calculate the 74.4?
 
Upvote 0
Then what does this mean:


Where did you add that? To get the 30 (which I think should be 30.05 if so).
Usually I add 3% to the purchase price to get the cost price. Now I have the value of the Purchase price which 74.40 divided by the factor 30 makes 2.48. Now to get the costs price I add 3% to the purchase price of 2.48 which is 2.55. I want to check if there is indeed 3% difference between the cost price and purchase price with all my products, but I get a different number with my formula. So my question is, what am I doing wrong here.
 
Upvote 0
You have 2 issues.
The initial calculation is 1.03 x $ 2.48 = $ 2.5544.
The base of the 3% is 2.48 in your calculation above you are using 2.55 as the which will give you a smaller %
ie instead of .03/1 you are doing .03/1.03

The 2nd issue is that 2.55 is a round down of 2.5544, which also reduces your check calculation.
 
Upvote 0
Solution
You have 2 issues.
The initial calculation is 1.03 x $ 2.48 = $ 2.5544.
The base of the 3% is 2.48 in your calculation above you are using 2.55 as the which will give you a smaller %
ie instead of .03/1 you are doing .03/1.03

The 2nd issue is that 2.55 is a round down of 2.5544, which also reduces your check calculation.
Thank you for your answer, I can use this to solve the issue.
 
Upvote 0

Forum statistics

Threads
1,223,228
Messages
6,170,871
Members
452,363
Latest member
merico17

We've detected that you are using an adblocker.

We have a great community of people providing Excel help here, but the hosting costs are enormous. You can help keep this site running by allowing ads on MrExcel.com.
Allow Ads at MrExcel

Which adblocker are you using?

Disable AdBlock

Follow these easy steps to disable AdBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the icon in the browser’s toolbar.
2)Click on the "Pause on this site" option.
Go back

Disable AdBlock Plus

Follow these easy steps to disable AdBlock Plus

1)Click on the icon in the browser’s toolbar.
2)Click on the toggle to disable it for "mrexcel.com".
Go back

Disable uBlock Origin

Follow these easy steps to disable uBlock Origin

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back

Disable uBlock

Follow these easy steps to disable uBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back
Back
Top