Deleting Last Word in the Cell based on Condition

madhuchelliah

Board Regular
Joined
Nov 22, 2017
Messages
226
Office Version
  1. 2019
Platform
  1. Windows
Hello all, i want to delete the last word in the cell if it is not equal "OK". My data is in A column and range is dynamic. The macro has look into all the cells in the column and delete the last word, if it is not equal to "OK". Thank you.
 

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Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.
Try this with a copy of your workbook.

VBA Code:
Sub Delete_Last_Word()
  With Range("A2", Range("A" & Rows.Count).End(xlUp))
    .Value = Evaluate(Replace("if(#="""","""",if(right(#,3)="" OK"",#,trim(left(#,len(#)-len(trim(right(substitute(#,"" "",rept("" "",50)),50)))))))", "#", .Address))
  End With
End Sub
 
Upvote 0
Solution
A loop should do it if the data range is not too large
Code:
Sub With_A_Loop()
Dim c As Range
    For Each c In Range("A2:A" & Cells(Rows.Count, 1).End(xlUp).Row)
        If Mid(c, InStrRev(c, " ") + 1, 99) <> "OK" Then c.Value = Left(c, InStrRev(c, " ") - 1)
    Next c
End Sub

Peter is way ahead of me, both in time and excel intelligence with that code.
 
Upvote 0
A loop should do it if the data range is not too large
Just a couple of comments
  1. Your code will error if there are any blank cells or cells with only one word.
  2. A shorter way of testing
    If Mid(c, InStrRev(c, " ") + 1, 99) <> "OK"
    would be
    If Right(c, 3) <> " OK"
 
Upvote 0
You're right. Too much in a hurry.
Thanks Peter.
 
Upvote 0
Try this with a copy of your workbook.

VBA Code:
Sub Delete_Last_Word()
  With Range("A2", Range("A" & Rows.Count).End(xlUp))
    .Value = Evaluate(Replace("if(#="""","""",if(right(#,3)="" OK"",#,trim(left(#,len(#)-len(trim(right(substitute(#,"" "",rept("" "",50)),50)))))))", "#", .Address))
  End With
End Sub
Thanks Peter, it is working fine. Thanks for your time.
 
Upvote 0

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