Creating a variable cell reference in a 'sorting' macro

[George Philp]

Sub All()
'
' All Macro
'
' Keyboard Shortcut: Ctrl+z
'
Range("A6:Z23").Select
ActiveWorkbook.Worksheets("All").Sort.SortFields.Clear
ActiveWorkbook.Worksheets("All").Sort.SortFields.Add Key:=Range("Z6:Z23"), _
SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal
ActiveWorkbook.Worksheets("All").Sort.SortFields.Add Key:=Range("U6:U23"), _
SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal
With ActiveWorkbook.Worksheets("All").Sort
.SetRange Range("A6:Z23")
.Header = xlGuess
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply
End With
End Sub

This macro sorts data in a spreadsheet, and whilst the ‘top left’ value is fixed (A6, Z6, and U6) the bottom right value (Z23 and U23) is variable dependent on the number of rows in the spreadsheet. I do have a cell which is a count of the number of rows to sort (18 in this spreadsheet). Is there any way that I can code this in the macro to save me from editing the macro if rows are added/deleted? It would in effect be (for example) “Z” concatenated with “5 plus this cell value”.

 

[James006]

Hello,

You can a variable such as last

last = Worksheets("All").Cells(Rows.Count, 1).End(xlUp).Row

and then use it as follows:

Range("A6:Z"&last)

Hope this will help

 

[George Philp]

Hi James006.

Thank you so much for your speedy and helpful reply.

I am very much a novice in comparison to your obvious Excel skills! I'm afraid I can't follow your code, but the variable that I need 'last' to be will always be in cell AA1 on the 'All' sheet.

I have tried last = "All"!AA1 and a few other permutations, but no joy

Thanks in advance!
George

 

[James006]

Hi,

With the variable last ... there is no need for cell AA1 to hold the total number of rows ...

Should you still want to use the contents of cell AA1 :

last = Worksheets("All").Range("AA1").Value

Hope this will help

 

[George Philp]

James006 - you are a star Sir!

Thank you so much. Works perfectly.

Best regards,
George

 

[James006]

You are welcome