Creating a unique list of values from a selection in multiple columns

Spartanjuli1

New Member
Joined
Sep 13, 2016
Messages
13
Office Version
  1. 365
Platform
  1. Windows
Hello everyone,

In the table attached, I have "intervals" from column A to C
The content shows "Hours" for each interval.

col Acol Bcol C
Row 1
1​
2​
3​
Row 2
1000​
2000​
1200​
Row 3
350​
700​
1050​
Row 4
1000​
800​
3000​
Row 5
350​
700​
1050​
Row 6
400​
2000​
3000​



I want to pull out a single list out of those 3 columns into a single one as the following:
List with unique values based on selection from A2:C6
List
350
400
700
800
1000
1050
1200

I checked various topics but not able to find this particular one.

Thank you for helping there.
Regards
 

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Excel Facts

How can you automate Excel?
Press Alt+F11 from Windows Excel to open the Visual Basic for Applications (VBA) editor.
Try this:
Book1.xlsx
ABCDEFG
1123Unique ValuesVersion 2
210002000120010001000
3350700105020002000
41000800300012001200
53507001050350350
640020003000700700
710501050
8800800
930003000
10400400
11 
12 
13 
Sheet1
Cell Formulas
RangeFormula
F2:F10F2=INDEX($A$2:$C$6, MIN(IF(COUNTIF($F$1:F1, $A$2:$C$6)=0, ROW($A$2:$C$6)-MIN(ROW($A$2:$C$6))+1)), MATCH(0, COUNTIF($F$1:F1, INDEX($A$2:$C$6, MIN(IF(COUNTIF($F$1:F1,$A$2:$C$6)=0, ROW($A$2:$C$6)-MIN(ROW($A$2:$C$6))+1)), , 1)), 0), 1)
E2:E13E2=INDIRECT(TEXT(MIN(IF(($A$2:$C$6<>"")*(COUNTIF($E$1:E1,$A$2:$C$6)=0),ROW($2:$6)*100+COLUMN($A:$C),7^8)),"R0C00"),)&""
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Last edited:
Upvote 0
Solution
Hello,
That's great this way and working really good !
Last challenge on this one if possible: how would it be possible to sort them from smallest to largest ?

That would be it.
Thank you a lot
 
Upvote 0
Please Upload Account Detail to we Know what version of Excel & Os you Used. to Help based on.
For example if you have office 365 you can Use Sort function.
 
Upvote 0
Because You have Office 365 Try this Easy Method.

Excel Formula:
=SORT(UNIQUE(FILTER(A2:C6,A2:C6<>"")))
 
Upvote 0
Hello,

Sorry for the time to answer here, I tried as well with the SORT and it works, great tip !

Have a good day,
I am grateful for your assistance !
 
Upvote 0
Here is an additional VBA based solution.
Select the area where the values are and run the macro "TS_Values_Count_Sort"

VBA Code:
Sub TS_Values_Count_Sort()

On Error GoTo ErrHand
Application.Calculation = xlManual: Application.ScreenUpdating = False: Application.DisplayAlerts = False

    Dim SeaRNG As Range, ResRNG As Range, Cell As Range
    Set SeaRNG = Selection
    Dim Tmp As Single ' If need count strings then change to As String
    Dim dict As Object: Set dict = CreateObject("Scripting.Dictionary")
    Dim dictNew As Object: Set dictNew = CreateObject("Scripting.Dictionary")
    Dim ARL As Object: Set ARL = CreateObject("System.Collections.ArrayList")
    Dim key As Variant, keyN As Variant, i As Integer
            
    Set ResRNG = Range("E1") ' Range to return values (Writes to E Columns)
        For Each Cell In SeaRNG
            Tmp = Cell.Value
            If dict.exists(Tmp) Then
                dict(Tmp) = dict(Tmp) + 1
            Else
                dict.Add (Tmp), 1
           End If
        Next
        
    'dictionary To Arraylist
    For Each key In dict
        ARL.Add key
    Next key
    
    ' Sort the keys
    ARL.Sort
    'ARL.Reverse
    
    For Each keyN In ARL
        dictNew.Add keyN, dict(keyN)
    Next keyN

            i = 1
            ResRNG.Value = "Value" ': ResRNG.Offset(0, 1).Value = "Count"
            
                For Each key In dictNew.Keys
                    'If dictNew(key) = 1 Then
                            ResRNG.Offset(i).Value = key
                            'ResRNG.Offset(i, 1).Value = dict(key)
                            i = i + 1
                    'End If
                Next key


                
ErrHand:
Application.Calculation = xlAutomatic: Application.ScreenUpdating = True: Application.DisplayAlerts = True
If Err.Number <> 0 Then MsgBox "Something went badly wrong!" & vbCrLf & "VBA-code is ended!" & vbCrLf & vbCrLf & "Error number: " & Err.Number & " " & Err.Description: End

End Sub
 
Upvote 0

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