TheHighlandCal
New Member
- Joined
- Nov 12, 2018
- Messages
- 1
Hi all,
Looking for some help on this problem.
I have 5 different columns with different measurements (these can be anything) and want to create a list of all the different unique combinations and then count how many of each unique combination there is.
There can be thousands of different entries so I am looking to completely automate this. The Table will look something like this:
[TABLE="class: grid, width: 700, align: center"]
<tbody>[TR]
[TD][/TD]
[TD]Measurement 1[/TD]
[TD]Measurement 2[/TD]
[TD]Measurement 3[/TD]
[TD]Measurement 4[/TD]
[TD]Measurement 5[/TD]
[TD]Type[/TD]
[/TR]
[TR]
[TD]P01[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e[/TD]
[TD]Type A[/TD]
[/TR]
[TR]
[TD]P02[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e'[/TD]
[TD]Type B[/TD]
[/TR]
[TR]
[TD]P03[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e[/TD]
[TD]Type A[/TD]
[/TR]
</tbody>[/TABLE]
Once I achieve this counting the different types will be simple.
I hope this is clear and any help given will be greatly appreciated!
Looking for some help on this problem.
I have 5 different columns with different measurements (these can be anything) and want to create a list of all the different unique combinations and then count how many of each unique combination there is.
There can be thousands of different entries so I am looking to completely automate this. The Table will look something like this:
[TABLE="class: grid, width: 700, align: center"]
<tbody>[TR]
[TD][/TD]
[TD]Measurement 1[/TD]
[TD]Measurement 2[/TD]
[TD]Measurement 3[/TD]
[TD]Measurement 4[/TD]
[TD]Measurement 5[/TD]
[TD]Type[/TD]
[/TR]
[TR]
[TD]P01[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e[/TD]
[TD]Type A[/TD]
[/TR]
[TR]
[TD]P02[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e'[/TD]
[TD]Type B[/TD]
[/TR]
[TR]
[TD]P03[/TD]
[TD]a[/TD]
[TD]b[/TD]
[TD]c[/TD]
[TD]d[/TD]
[TD]e[/TD]
[TD]Type A[/TD]
[/TR]
</tbody>[/TABLE]
Once I achieve this counting the different types will be simple.
I hope this is clear and any help given will be greatly appreciated!