Counting multiple columns

datadummy

Active Member
Joined
Mar 16, 2017
Messages
313
Office Version
  1. 365
Platform
  1. Windows
I need assistance writing multiple countif statements. Example countif 'Sheet1'!C1:C100,"Y" or if 'Sheet1'!D1:D100,"Y". I currently have it written as follows, =COUNTIFS('Post-Visit-Call-Raw-Data'!AE:AE,"Y",OR(IF('Post-Visit-Call-Raw-Data'!AL:AL,"Y"))) and am getting an error. Thanks in advance.
 

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Here is one way:
Code:
[COLOR=#333333]=COUNTIF('Post-Visit-Call-Raw-Data'!AE:AE,"Y") + COUNTIF('Post-Visit-Call-Raw-Data'!AL:AL,"Y") - COUNTIFS([/COLOR][COLOR=#333333]'Post-Visit-Call-Raw-Data'!AE:AE,"Y",[/COLOR][COLOR=#333333]'Post-Visit-Call-Raw-Data'!AL:AL,"Y")[/COLOR]
 
Upvote 0
Easier way is to sum your answers

=SUM(COUNTIF('Post-Visit-Call-Raw-Data'!AE:AE,"Y"),COUNTIF('Post-Visit-Call-Raw-Data'!AL:AL,"Y"))
 
Upvote 0
I didn't do a very good job explain my ask, what I am trying to do is look at the columns above (AE & AN) but rather than adding them together I'm looking for a statement that will essentially say if either one has "Y" in it then count it as Y in a composite field. Hope this helps, sorry for any confusion.
 
Upvote 0
I didn't do a very good job explain my ask, what I am trying to do is look at the columns above (AE & AN) but rather than adding them together I'm looking for a statement that will essentially say if either one has "Y" in it then count it as Y in a composite field. Hope this helps, sorry for any confusion.
That is what my solution does. It counts the number of rows where a Y occurs in either column.

The logic is this:
- Add the total number of rows where "Y" occurs in column AE to the total number of rows where "Y" occurs in column AN.
- However, that could lead to "double-counting", if "Y" occurs in BOTH columns AE and AN for some rows.
- How do we account for that? Simply, subtract the number of rows where both columns "AE" and "AN" contain a "Y".

That is how my solution works.
Have you tried both of the solutions presented to see if they work?
 
Upvote 0

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