CountIFS Assistance Please

Taff

Board Regular
Joined
Mar 31, 2004
Messages
151
Office Version
  1. 365
Platform
  1. Windows
  2. Web
I have this formula which returns a correct result:
=COUNTIFS(E0!BP2:BP2910,">2.5",E0!AZ2:AZ2910,">2.2",E0!AZ2:AZ2910,"<2.7")

When I substitute the exact criteria with a cell reference, with the same criteria in, I get a 0
=COUNTIFS(E0!BP2:BP2910,">A4",E0!AZ2:AZ2910,">B4",E0!AZ2:AZ2910,"<C4")

I am trying to build a query where I can quickly point/change to the criteria without having to go in and change each formula.

Any ideas how to achieve would be appreciated.

Thanks

Taff
 

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Hi,

Your values in A4, B4, and the missing third, are they manually entered or from a formula?
Your original formula using 2.5 is a number, but is different if A4 is "2.5" (which is Text).
 
Last edited:
Upvote 0
they are manually entered.

the countifs formula appears to enter them as text automatically. I have tried removing the "" but it won't let me.

well spotted the formula not working is:
=COUNTIFS(E0!BP2:BP2910,">A4",E0!AZ2:AZ2910,">B4",E0!AZ2:AZ2910,"<C4")
 
Upvote 0
they are manually entered.

the countifs formula appears to enter them as text automatically. I have tried removing the "" but it won't let me.

What do you mean it won't let you?
 
Upvote 0
=COUNTIFS(E0!BP2:BP2910,">"&A4,E0!AZ2:AZ2910,">"&B4,E0!AZ2:AZ2910,"<"&C4)

where A4 = 2.5, B4 = 2.2, and C4 = 2.7, would produce the same result as:

=COUNTIFS(E0!BP2:BP2910,">2.5",E0!AZ2:AZ2910,">2.2",E0!AZ2:AZ2910,"<2.7")


 
Last edited:
Upvote 0
Aladin's correct, you have your "" quotes misplaced in your formula.
 
Upvote 0
You're welcome, glad you have it working.
 
Upvote 0

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