CountIF Formula if cell is yellow and has Satisfactory

[squeakums]

How would I got about writing a countif formula if the cell is yellow and has satisfactory 'text' in it? 2 Factors for count if please?

 

[MARK858]

You can't as a formula can't detect a colour, you either have to test for the condition that the cell is coloured based on or use a VBA function (and even then it depends whether your cell is coloured by fill colour or conditional formatting).

 

[squeakums]

I was trying to use the VBA code on the sheet which I googled and go from there in the countif formula option. Any idea how I would set something like this up to work?

 

[MARK858]

How is the cell coloured with a manual fill or conditional formatting?

 

[squeakums]

It's colored manually by another group.

 

[MARK858]

Try putting the code below in a regular module, then use the formula below.
Please note that it will only pick up the standard yellow, if they don't use it then we can change the code so that it is based on one of the cells fill color.

Function ColorFunction(rRange As Range)
    Dim rCell As Range, vResult
    Application.Volatile
    
    For Each rCell In rRange
        If rCell.Interior.ColorIndex = 6 And rCell.Value = "satisfactory" Then vResult = 1 + vResult
    Next rCell

    ColorFunction = vResult
End Function

Book1
	A	B	C
1
2
3
4
5			3
6	satisfactory
7
8
9
10
11
12	satisfactory
13	satisfactory
14	satisfactory
15
16
17
18
Sheet4

Cell Formulas
Range	Formula
C5	=ColorFunction(A1:A17)