Count Values Greater Than Measure Average

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How to find 2nd largest value in a column?
MAX finds the largest value. =LARGE(A:A,2) will find the second largest. =SMALL(A:A,3) will find the third smallest
Hi,

Yes it can be done in measure, and i have one suggestion:

1. You can use standard MEDIAN() DAX formula
MEDIAN_NEW:=MEDIAN(Tabela1[Average])


2. Now the calculation looks like this:
Above MEDIAN:=
VAR
MEDIANCALC = [MEDIAN_NEW]
RETURN
SUMX(Tabela1; (Tabela1[Average]>MEDIANCALC)*1)

Variables are used to avoid using allexcept() in median calculations
 
Last edited:
Upvote 0
Hi,

Yes it can be done in measure, and i have one suggestion:

1. You can use standard MEDIAN() DAX formula
MEDIAN_NEW:=MEDIAN(Tabela1[Average])


2. Now the calculation looks like this:
Above MEDIAN:=
VAR
MEDIANCALC = [MEDIAN_NEW]
RETURN
SUMX(Tabela1; (Tabela1[Average]>MEDIANCALC)*1)

Variables are used to avoid using allexcept() in median calculations

ralliartur,

MEDIAN() isnt a function in the 2013 DAX Library. Im using this library.

However, how do I implement this new measure?

All of this below I put into the cell in PowerPivot?
Above MEDIAN:=
VAR
MEDIANCALC = [MEDIAN_NEW]
RETURN
SUMX(Tabela1; (Tabela1[Average]>MEDIANCALC)*1)


Ive tried this syntax, resulting in a error.
 
Upvote 0
ralliartur,
MEDIAN() isnt a function in the 2013 DAX Library. Im using this library.

Sorry, VARS are not in Excel2013 Either

in this case Above MEDIAN:=SUMX(Tabela1; (Tabela1[Average]>CALCULATE([MEDIAN];ALLEXCEPT(Tabela1;Tabela1[Category];Tabela1[Subcategory])))*1)
 
Upvote 0
Sorry, VARS are not in Excel2013 Either

in this case Above MEDIAN:=SUMX(Tabela1; (Tabela1[Average]>CALCULATE([MEDIAN];ALLEXCEPT(Tabela1;Tabela1[Category];Tabela1[Subcategory])))*1)

ralliartur, works fine for me!

Thank you a lot for your support.

When writing in Excel we can use F9 to evaluate step-by-step calculations. Thats different in this case. Why did you use *1 at the end of phrase?? Convert the TRUE/FALSE matrix in 1/0??
 
Upvote 0

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