Count the cells with specific Font color within the range of cell that have a specific background color

kalinajo

New Member
Joined
Jan 21, 2019
Messages
2
Hi all,

I want to know how much cell have a blue Font color within the cells that have a green background (and so on, 5 background colors and 5 Font colors).

Exemple: I have 20 cells that have a green background, from those cells how much have a blue Font?

Here are my formulas:

Background color count:

Function ColorCount(SearchRange As Range, colorRange As Range) As Long
Dim cell As Range, a As Range, b As Range, n As Integer

' preload for Union method (will Union with itself in first For loop)
Set b = SearchRange(1).MergeArea(1)

For Each cell In SearchRange
Set a = cell.MergeArea(1)
Set b = Union(a, b)
Next

' a becomes the preload for the next Union; n will be used to exclude
' it from the count if it's not the right color
n = a.Interior.Color = colorRange.Interior.Color

For Each cell In b
If cell.Interior.Color = colorRange.Interior.Color Then
Set a = Union(cell, a)
End If
Next

ColorCount = a.Count - 1 - n

End Function
-------------------------------------

*Please note that I need to use some merged cells in my file (no way out of it) and I need them to count as one cell. This Function seems to work perfectly for that.

Font Color count:

Function FontColorCount(SearchRange As Range, colorRange As Range) As Long
Dim cell As Range, a As Range, b As Range, n As Integer

' preload for Union method (will Union with itself in first For loop)
Set b = SearchRange(1).MergeArea(1)

For Each cell In SearchRange
Set a = cell.MergeArea(1)
Set b = Union(a, b)
Next

' a becomes the preload for the next Union; n will be used to exclude
' it from the count if it's not the right color
n = a.Font.Color = colorRange.Font.Color

For Each cell In b
If cell.Font.Color = colorRange.Font.Color Then
Set a = Union(cell, a)
End If
Next

FontColorCount = a.Count - 1 - n

End Function
---------------------------

I am stuck there! Help! I don't know how to use a function within an other one. Also would I need to use a Find function instead of a count Function ie: =Count Font color = Reference cell, IF(Background color = Reference cell) (Rough idea of what I want to do).

Thank you all for your support!
 

Excel Facts

Return population for a City
If you have a list of cities in A2:A100, use Data, Geography. Then =A2.Population and copy down.
Try this

[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD][/TD]
[TD]A[/TD]
[TD]B[/TD]
[TD]C[/TD]
[TD]D[/TD]
[/TR]
[TR]
[TD="align: center"]1[/TD]
[TD][/TD]
[TD][/TD]
[TD="bgcolor: #92d050"]HI[/TD]
[TD="align: right"]2[/TD]
[/TR]
[TR]
[TD="align: center"]2[/TD]
[TD][/TD]
[TD]B2[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD="align: center"]3[/TD]
[TD][/TD]
[TD="bgcolor: #92d050"]B3[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD="align: center"]4[/TD]
[TD][/TD]
[TD]B4[/TD]
[TD][/TD]
[TD][/TD]
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[TR]
[TD="align: center"]5[/TD]
[TD][/TD]
[TD]B5[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD="align: center"]6[/TD]
[TD][/TD]
[TD="bgcolor: #92d050"]B6[/TD]
[TD][/TD]
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[TD="align: center"]7[/TD]
[TD][/TD]
[TD="bgcolor: #92d050"]B7[/TD]
[TD][/TD]
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[TD="align: center"]8[/TD]
[TD][/TD]
[TD]B8[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

Formula
CellFormula
D1=ColorInteriorFontCount(B2:B8,C1)

<tbody>
</tbody>

<tbody>
</tbody>



Code:
Function ColorInteriorFontCount(SearchRange As Range, colorRange As Range) As Long
    Dim cell As Range, a As Range, b As Range, n As Integer
    
    ' preload for Union method (will Union with itself in first For loop)
    Set b = SearchRange(1).MergeArea(1)
    
    For Each cell In SearchRange
        Set a = cell.MergeArea(1)
        Set b = Union(a, b)
    Next
    
    ' a becomes the preload for the next Union; n will be used to exclude
    ' it from the count if it's not the right color
    n = a.Interior.Color = colorRange.Interior.Color
    
    For Each cell In b
        If cell.Interior.Color = colorRange.Interior.Color And _
           cell.Font.Color = colorRange.Font.Color Then
            Set a = Union(cell, a)
        End If
    Next
    
    ColorInteriorFontCount = a.Count - 1 - n


End Function
 
Last edited:
Upvote 0
Thank you very much! It works perfectly!! :)

Try this

Code:
Function ColorInteriorFontCount(SearchRange As Range, colorRange As Range) As Long
    Dim cell As Range, a As Range, b As Range, n As Integer
    
    ' preload for Union method (will Union with itself in first For loop)
    Set b = SearchRange(1).MergeArea(1)
    
    For Each cell In SearchRange
        Set a = cell.MergeArea(1)
        Set b = Union(a, b)
    Next
    
    ' a becomes the preload for the next Union; n will be used to exclude
    ' it from the count if it's not the right color
    n = a.Interior.Color = colorRange.Interior.Color
    
    For Each cell In b
        If cell.Interior.Color = colorRange.Interior.Color And _
           cell.Font.Color = colorRange.Font.Color Then
            Set a = Union(cell, a)
        End If
    Next
    
    ColorInteriorFontCount = a.Count - 1 - n


End Function
 
Upvote 0
Try this

ABCD
1HI2
2B2
3B3
4B4
5B5
6B6
7B7
8B8

<tbody>
</tbody>

Formula
CellFormula
D1=ColorInteriorFontCount(B2:B8,C1)

<tbody>
</tbody>

<tbody>
</tbody>



Code:
Function ColorInteriorFontCount(SearchRange As Range, colorRange As Range) As Long
    Dim cell As Range, a As Range, b As Range, n As Integer
 
    ' preload for Union method (will Union with itself in first For loop)
    Set b = SearchRange(1).MergeArea(1)
 
    For Each cell In SearchRange
        Set a = cell.MergeArea(1)
        Set b = Union(a, b)
    Next
 
    ' a becomes the preload for the next Union; n will be used to exclude
    ' it from the count if it's not the right color
    n = a.Interior.Color = colorRange.Interior.Color
 
    For Each cell In b
        If cell.Interior.Color = colorRange.Interior.Color And _
           cell.Font.Color = colorRange.Font.Color Then
            Set a = Union(cell, a)
        End If
    Next
 
    ColorInteriorFontCount = a.Count - 1 - n


End Function
Hi, i try ur code but i had issue..

the count included A1 . A1 is the font colour i want to trigger.. dont know why is 3.. should be 2

Random_Macro.xlsm
ABCDEFGHIJKLMNOPQRSTUVW
1purpleredgreenorange brown123456789101112131415161718
23PPPBBBBBB
Sheet1
Cell Formulas
RangeFormula
A2A2=ColorInteriorFontCount(F2:W2,A1)
 
Last edited:
Upvote 0

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