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Count consecutive cells that matching a criteria, Starting from the very first cell
- Thread starter Shameer
- Start date
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- Tags
- consecutive count
Sham Let's get the ball rollin. We have to start somewhere. Now I modified your example, but the first 5 numbers should be the same. I have a question on your answer of 1. Your criteria of consecutive occurrences of values greater than 1% and less than 3% doesn't add up when 2.5, 1.31 and 2.18 would be 2 times. Unless I am misunderstanding your criteria, which is what I normally do, the example below answer should be 3. So let the question, comments or suggestions begin. We can always modify the solution to fit any criteria.
VBA Code:
Sub Prog1()
Dim LastCel As Integer
Dim count1 As Integer
count1 = 0
LastCel = Cells(Rows.Count, "C").End(xlUp).Row
For i = 5 To LastCel
Cells(i, 3).Select
If Cells(i, 3) > 0.01 And Cells(i, 3) < 0.03 And Cells(i + 1, 3) > 0.01 And Cells(i + 1, 3) < 0.03 Then
MsgBox Cells(i, 3)
count1 = count1 + 1
End If
Next i
Range("D3") = count1
End Sub| 23-10-01 work 1.xlsm | |||||
|---|---|---|---|---|---|
| B | C | D | |||
| 3 | Count is | 3 | |||
| 4 | |||||
| 5 | 246.38 | 1.56% | |||
| 6 | 240.5 | 4.04% | |||
| 7 | 244.12 | 2.50% | |||
| 8 | 246.99 | 1.31% | |||
| 9 | 244.88 | 2.18% | |||
| 10 | 255.7 | 5.00% | |||
| 11 | 262.59 | 4.00% | |||
| 12 | 266.5 | 1.25% | |||
| 13 | 265.28 | 2.30% | |||
| 14 | 274.39 | 8.00% | |||
Data | |||||
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Thanx for the lightning response #Exguy4u!!.
I guess I did not explain it well (which is I what I normally do
).
In the Column "Variations compared to Today", I need to count:
- cells that meet the criteria 'greater than 1% and less than 3%'
- starting from very First cell
- up to the cell after which the criteria fails
In the example I uploaded earlier, first cell of column meets the criteria. Second cell of column fails the criteria. So the count is 1.
In the new example I am uploading with this reply, the count would be be 3 (first 3 cells meets the criteria and 4th cell fails the criteria)).
Trust this explanation makes my question clearer.
Fyi, I see a very old post from 2017 that seems very similar to my question. My knowledge was not enough to adapt that formula for my need.
www.mrexcel.com
Thanx again.
I guess I did not explain it well (which is I what I normally do
).In the Column "Variations compared to Today", I need to count:
- cells that meet the criteria 'greater than 1% and less than 3%'
- starting from very First cell
- up to the cell after which the criteria fails
In the example I uploaded earlier, first cell of column meets the criteria. Second cell of column fails the criteria. So the count is 1.
In the new example I am uploading with this reply, the count would be be 3 (first 3 cells meets the criteria and 4th cell fails the criteria)).
Trust this explanation makes my question clearer.
Fyi, I see a very old post from 2017 that seems very similar to my question. My knowledge was not enough to adapt that formula for my need.
Count Consecutive Cells from a starting point
Hello. I am trying to have a formula that will count the number of consecutive cells using a starting point. I have used the threads to find the number of consecutive cells in a range but I only want to have the number of consecutive cells starting at the left most. Below is an example where...
Thanx again.
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Sham, I believe I have covered all the different scenarios. Now the thing about this web site, in my opinion, is that how we ask the question to solve our problems is a big part. Once the community sees your input and output, using this XL2BB, they have a better idea of other solutions. So maybe an A+ student will weigh in and show us a better solution. In the meantime, this program should give you what you want.
VBA Code:
Sub Prog3()
Dim LastCel As Integer
Dim count1 As Integer
Dim Trap As Boolean
Trap = False
count1 = 0
LastCel = Cells(Rows.Count, "C").End(xlUp).Row
If Cells(5, 3) > 0.01 And Cells(5, 3) < 0.03 Then
Trap = True
End If
For i = 5 To LastCel
Cells(i, 3).Select
If Cells(i, 3) > 0.01 And Cells(i, 3) < 0.03 And Trap = True Then
Trap = True
count1 = count1 + 1
End If
If count1 >= 1 And Trap = False Then
Exit For
End If
If Cells(i + 1, 3) > 0.01 And Cells(i + 1, 3) < 0.03 Then
Trap = True
Else
Trap = False
End If
Next i
Range("D3") = count1
End Sub| 23-10-01 work 2.xlsm | |||||||||
|---|---|---|---|---|---|---|---|---|---|
| B | C | D | E | F | G | H | |||
| 3 | Count is | 1 | |||||||
| 4 | |||||||||
| 5 | 265.28 | -9.35% | -8.81% | -9.35% | 2.18% | -9.35% | |||
| 6 | 274.39 | 2.50% | -9.35% | -7.77% | -7.77% | 2.50% | |||
| 7 | 246.38 | -7.77% | -7.77% | 2.50% | 2.50% | -7.77% | |||
| 8 | 240.5 | -5.68% | 2.50% | -5.68% | -5.68% | -5.68% | |||
| 9 | 244.12 | 1.31% | 1.31% | 1.31% | 1.31% | 1.31% | |||
| 10 | 246.99 | 2.18% | 2.18% | 2.18% | -9.35% | 2.18% | |||
| 11 | 244.88 | -2.14% | -2.14% | -2.14% | -2.14% | -2.14% | |||
| 12 | 255.7 | -4.71% | -4.71% | -4.71% | -4.71% | -4.71% | |||
| 13 | 262.59 | -6.11% | -6.11% | -6.11% | -6.11% | -6.11% | |||
| 14 | 266.5 | -8.81% | -5.68% | -8.81% | -8.81% | -8.81% | |||
Data 3 | |||||||||
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bebo021999
Well-known Member
- Joined
- Jul 14, 2011
- Messages
- 2,541
- Office Version
- 2016
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Solution
Amazing....
Two simple questions.
I want to make the formula portable to start from any row. So, I changed the hard coded "-4" (see below image) to 'cell reference' (e.g., ROW(C4)).
Is that correct and will it work?? (It seems to work, but I prefer to have the Author's confirmation)
Second, in order to achieve the same results from a row of data (instead of column of data), will changing row to column, work (like in below example)??
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Thanx again #Exguy4u. I am an absolute rookie in VBA and could not implement your suggestion properly. I am sure someone else would find it useful in the near future.
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Thank you for your time and efforts
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