conditional formatting, REGEX to excel, do not want VBA, for tag numbers

cty43945

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May 18, 2018
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I am trying to make a workbook that ranchers and farmers can use (for free) for livestock inventory that does not use VBA (know some excel, and seem to always be learning more), to improve animal disease traceability.

1) AIN tag (15 characters), is ^(?!999)((840)|(124)|(484)|(9[0-9]{2}))[0-9]{12}$ , but even this could be updated. The 840 at the beginning, is always 840003, and then 9 more random digits. I thought it would be easy, but every time I think I have it, it doesn't work. I want the cell to highlight when entered incorrectly, but not highlight if nothing is entered... I am new to this, but thus far have : =NOT(AND(LEN($D2)=15,ISNUMBER($D2),OR(LEFT($D2,3)<>"999",LEFT($D2,6)="840003",LEFT($D2,3)="124",LEFT($D2,3)="484",AND(LEFT($D2,3)>"899",LEFT($D2,3)<"999",NOT(ISBLANK($D2)))))), which is not correct yet.

2) NUES tag (9 characters) is ^([0-9]{2}|MD|MN|NM|NY|US|WA|WY)[A-Z]{3}[0-9]{4}$ The first two characters are the numeric state code, or sometimes also the actual state abbreviation (for those listed). Then it is 3 letters, and 4 numbers. I found an example, modified its logic, and it almost works. But if possible, I do not want a reference cell. The letters do need to be all caps (for this and following example). I have =AND(LEN($C2)=9,OR(ISNUMBER(-MID($C2,ROW(INDIRECT("1:2")),1)),LEFT($C2,2)="MD",LEFT($C2,2)="MN",LEFT($C2,2)="NM",LEFT($C2,2)="NY",LEFT($C2,2)="US",LEFT($C2,2)="WA",LEFT($C2,2)="WY"),FIND(MID($C2,ROW(INDIRECT("3:5")),1),Letters),ISNUMBER(-MID($C2,ROW(INDIRECT("6:9")),1))), and Letters is "ABCDEFGHIJKLMNOPQRSTUVWXYZ". It works, but when lowercase letters are entered, it does not highlight, #VALUE . I would like to not use a reference if possible (the A-Z). I know how to make string upper, or lower, but not make a true false out of it. Also what I have highlights all empty cells. I was trying the Or Not(IsBlank... but it kept breaking it...

3) and AGE/Birthdate column: This can be 3M for 3 Months, 4Y for 4 years, or can be the actual birthdate.

^(([1-9][0-9]{0,2})(D|M|Y))$|^([1-9][0-9]{0,1}Y(([1][0-2])|[1-9])M)$|^((0?[13578]|10|12)(\/)(([1-9])|(0[1-9])|([12])([0-9]?)|(3[01]?))(\/)((19)([8-9])(\d{1})|(20)([0-2])(\d{1})))|(0?[2469]|11)(\/)(([1-9])|(0[1-9])|([12])([0-9]?)|(30))(\/)((19)([8-9])(\d{1})|(20)([0-2])(\d{1}))$

There are more tag types, but if I can get help with these three, I can modify them to create the others. Thank you
 

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2) This highlighted the lower case, but it doesn't seem to maintain the len = 9...

=ISERR(NOT(AND(LEN($C2)=9,OR(ISNUMBER(-MID($C2,ROW(INDIRECT("1:2")),1)),LEFT($C2,2)="MD",LEFT($C2,2)="MN",LEFT($C2,2)="NM",LEFT($C2,2)="NY",LEFT($C2,2)="US",LEFT($C2,2)="WA",LEFT($C2,2)="WY"),FIND(MID($C2,ROW(INDIRECT("3:5")),1),Letters),ISNUMBER(-MID($C2,ROW(INDIRECT("6:9")),1)))))
 
Upvote 0
2) I was able to get rid of needing a named cell by completely changing my strategy of how to do this.

=EXACT($C2,LOWER($C2)) compares the actual value, to lowercase. If it is lowercase, it will be true. Could use upper to flip result (SEARCH is also case sensitive, but can't really use that one)

=AND(ISERR(VALUE(RIGHT($C2,5))>10000))
This formula looks at the last 5 digits, if there is 5, it will be greater than 10000. So it looks, If it is true, it will be red. If it is not, it will throw an error, which is why the ISERR( function is there. This will flip what you think would be returned. So if there are 5 digits on the end, then it will not throw an error, so false. If there isn't, true.

This works perfectly except it is still flagging blanks. The work around for blanks was an IF statement.

=IF(ISBLANK($C2),"FALSE",NOT(AND(ISNUMBER(VALUE(RIGHT($C2,4))),NOT(ISNUMBER(VALUE(MID($C2,3,3)))),OR(ISNUMBER(VALUE(LEFT($C2,2))),LEFT(C2,2)="MD",LEFT(C2,2)="MN",LEFT(C2,2)="NM",LEFT(C2,2)="NY",LEFT(C2,2)="US",LEFT(C2,2)="WA",LEFT(C2,2)="WY"),LEN(C2)=9,ISERR(VALUE(RIGHT($C2,5))>10000),EXACT($C2,UPPER($C2)))))

This one is complete. Any advice on 1) or 3) would be greatly appreciated
 
Upvote 0
1) is finished. =IF(ISBLANK($D2),"FALSE",NOT(AND(ISNUMBER(VALUE($D2)),LEN($D2)=15,OR(AND(LEFT($D2,3)<>"999",LEFT($D2,3)>="900"),LEFT($D2,6)="840003",LEFT($D2,3)="124",LEFT($D2,3)="484"))))

Any advice will be appreciated
 
Upvote 0
Thoughts about 2)
To ckeck the length...
LEN(A2)=9

To check the first two characters...
OR(ISNUMBER(--LEFT(A2,2)),ISNUMBER(MATCH(LEFT(A2,2),{"MD";"MN";"NM";"NY";"US";"WA";"WY"},0)))

To check if the 3rd, 4th and 5th characters are letters...
EXACT(UPPER(MID(A2,3,1)),LOWER(MID(A2,3,1)))=FALSE
EXACT(UPPER(MID(A2,4,1)),LOWER(MID(A2,4,1)))=FALSE
EXACT(UPPER(MID(A2,5,1)),LOWER(MID(A2,5,1)))=FALSE

To check if the 4 last characters are numbers...
ISNUMBER(--MID(A2,6,4))

M.
 
Last edited:
Upvote 0
I will definitely incorporate these in. The one issue I ran into is a common error is that they drop a letter, and add a number at the end, but the more thorough check on the 3rd, 4th, and 5th characters as letters should cover that.

Thank you for your help! I am trying it out now
 
Last edited:
Upvote 0
oops...

I think you cannot use array constants like {"MD";"MN";"NM";"NY";"US";"WA";"WY"} in Conditional Formatting.
So to check the first two characters create a named range, say MyList, and use
OR(ISNUMBER(--LEFT(A2,2)),ISNUMBER(MATCH(LEFT(A2,2),MyList,0)))

M.
 
Upvote 0
I just ran into that. I also could use the OR(ISNUMBER(VALUE(LEFT($C2,2))),LEFT(C2,2)="MD",LEFT(C2,2)="MN",LEFT(C2,2)="NM",LEFT(C2,2)="NY",LEFT(C2,2)="US",LEFT(C2,2)="WA",LEFT(C2,2)="WY") part
 
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