Conditional correlation of returns

pathway1

New Member
Joined
Jan 10, 2023
Messages
2
Office Version
  1. 365
Platform
  1. Windows
Hello forum,
Thank you in advance for your help.
I need to create a correlation matrix (simple, edited pic attached) that returns the correlation coefficient of columns 1 and 2 for the subset of periods where a third column, Equity, is down at least -2%.
Within a conditional correlation, I nested a condition of what I thought was "if downside deviation exceeds -2%", which I expected to ignore any period when US equity was >-2%, thus return correlation of columns 1 and 2 for the subset of periods that I was looking for. Instead, it is just returning the correlation of columns 1 and 2. What have I missed here, and how do I fix it (Excel only)?

My incorrect attempt (cell A3):
=CORREL(IF(STDEV(IF($L$15:$L$29<-2%,$L$15:$L$29,"")), $A$15:$A$29),$B$15:$B$29)
 

Attachments

  • Correlation Question - Monthly Returns.JPG
    Correlation Question - Monthly Returns.JPG
    53.9 KB · Views: 22

Excel Facts

How can you turn a range sideways?
Copy the range. Select a blank cell. Right-click, Paste Special, then choose Transpose.
Using function FILTER is the easiest way to extract values from lists. Like this:

MrExcel posts19.xlsx
BCDEFGHIJ
3hurdle-2.0%correlation:-0.07772correlation (single cell):-0.07772
4
512ehelper 1helper 2
69.9%6.6%2.1%-3.1%7.8%
71.1%8.7%2.0%7.0%-4.9%
8-3.1%7.8%-3.0%-0.6%-7.3%
9-9.8%9.3%-1.0%1.6%8.6%
105.5%-9.2%5.0%5.0%7.6%
117.0%-4.9%-8.0%5.2%-2.2%
12-7.5%-1.9%-1.0%-1.7%-7.2%
13-1.5%5.9%-1.0%-5.9%6.5%
14-4.5%1.3%6.0%-9.5%-1.6%
151.2%5.1%6.0%
16-0.6%-7.3%-3.0%
17-7.9%-9.0%3.0%
181.6%8.6%-5.0%
195.0%7.6%-8.0%
205.2%-2.2%-9.0%
21-1.7%-7.2%-5.0%
22-3.7%7.4%5.0%
23-5.9%6.5%-10.0%
24-9.5%-1.6%-3.0%
Sheet37
Cell Formulas
RangeFormula
G3G3=CORREL(F6#,G6#)
J3J3=CORREL(FILTER(B6:B24,D6:D24<=D3),FILTER(C6:C24,D6:D24<=D3))
F6:F14F6=FILTER(B6:B24,D6:D24<=D3)
G6:G14G6=FILTER(C6:C24,D6:D24<=D3)
Dynamic array formulas.
Cells with Conditional Formatting
CellConditionCell FormatStop If True
D6:D24Cell Value<=$D$3textNO
 
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Solution

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