Dear Friends,
I had used the below function to count the number of cells in which conditional format is applied,it works fine with excel 2003.But not with 2007
IF(LEN($I2);CFColorCount(M$15:M$208;3);0)
Kindly help me to rectify this error
This is the function which works fine in 2003 not in 2007
Public Function CFColorindex(rng As Range, _
Optional text As Boolean = False)
Dim oFC As FormatCondition
Dim sF1 As String
Dim iRow As Long
Dim iColumn As Long
Set rng = rng(1, 1)
If rng.FormatConditions.Count > 0 Then
For Each oFC In rng.FormatConditions
If oFC.Type = xlCellValue Then
Select Case oFC.Operator
Case xlEqual
CFColorindex = rng.Value = oFC.Formula1
Case xlNotEqual
CFColorindex = rng.Value <> oFC.Formula1
Case xlGreater
CFColorindex = rng.Value > oFC.Formula1
Case xlGreaterEqual
CFColorindex = rng.Value >= oFC.Formula1
Case xlLess
CFColorindex = rng.Value < oFC.Formula1
Case xlLessEqual
CFColorindex = rng.Value <= oFC.Formula1
Case xlBetween
CFColorindex = (rng.Value >= oFC.Formula1 And _
rng.Value <= oFC.Formula2)
Case xlNotBetween
CFColorindex = (rng.Value < oFC.Formula1 Or _
rng.Value > oFC.Formula2)
End Select
Else
're-adjust the formula back to the formula that applies
'to the cell as relative formulae adjust to the activecell
With Application
iRow = rng.row
iColumn = rng.Column
sF1 = .Substitute(oFC.Formula1, "ROW()", iRow)
sF1 = .Substitute(sF1, "COLUMN()", iColumn)
sF1 = Replace(sF1, ";", ",")
sF1 = .ConvertFormula(sF1, xlA1, xlR1C1)
sF1 = .ConvertFormula(sF1, xlR1C1, xlA1, , rng)
End With
CFColorindex = rng.Parent.Evaluate(sF1)
End If
If CFColorindex Then
If text Then
If Not IsNull(oFC.Font.ColorIndex) Then
CFColorindex = oFC.Font.ColorIndex
End If
Else
If Not IsNull(oFC.Interior.ColorIndex) Then
CFColorindex = oFC.Interior.ColorIndex
End If
End If
Exit Function
End If
Next oFC
End If 'rng.FormatConditions.Count > 0
End Function
Public Function CFColorCount(rng As Range, _
ciValue, _
Optional text As Boolean = False)
Dim cell As Range, row As Range
Dim i As Long, j As Long
Dim aryColours As Variant
If rng.Areas.Count > 1 Then
CFColorCount = "#Too many areas!"
Exit Function
End If
If rng.Cells.Count = 1 Then
CFColorCount = -CLng(CFColorindex(rng, text) = ciValue)
Else
i = 0
For Each row In rng.Rows
i = i + 1
j = 0
For Each cell In row.Cells
j = j + 1
CFColorCount = CFColorCount - CLng(CFColorindex(cell, text) = ciValue)
Next cell
Next row
End If
End Function
I had used the below function to count the number of cells in which conditional format is applied,it works fine with excel 2003.But not with 2007
IF(LEN($I2);CFColorCount(M$15:M$208;3);0)
Kindly help me to rectify this error
This is the function which works fine in 2003 not in 2007
Public Function CFColorindex(rng As Range, _
Optional text As Boolean = False)
Dim oFC As FormatCondition
Dim sF1 As String
Dim iRow As Long
Dim iColumn As Long
Set rng = rng(1, 1)
If rng.FormatConditions.Count > 0 Then
For Each oFC In rng.FormatConditions
If oFC.Type = xlCellValue Then
Select Case oFC.Operator
Case xlEqual
CFColorindex = rng.Value = oFC.Formula1
Case xlNotEqual
CFColorindex = rng.Value <> oFC.Formula1
Case xlGreater
CFColorindex = rng.Value > oFC.Formula1
Case xlGreaterEqual
CFColorindex = rng.Value >= oFC.Formula1
Case xlLess
CFColorindex = rng.Value < oFC.Formula1
Case xlLessEqual
CFColorindex = rng.Value <= oFC.Formula1
Case xlBetween
CFColorindex = (rng.Value >= oFC.Formula1 And _
rng.Value <= oFC.Formula2)
Case xlNotBetween
CFColorindex = (rng.Value < oFC.Formula1 Or _
rng.Value > oFC.Formula2)
End Select
Else
're-adjust the formula back to the formula that applies
'to the cell as relative formulae adjust to the activecell
With Application
iRow = rng.row
iColumn = rng.Column
sF1 = .Substitute(oFC.Formula1, "ROW()", iRow)
sF1 = .Substitute(sF1, "COLUMN()", iColumn)
sF1 = Replace(sF1, ";", ",")
sF1 = .ConvertFormula(sF1, xlA1, xlR1C1)
sF1 = .ConvertFormula(sF1, xlR1C1, xlA1, , rng)
End With
CFColorindex = rng.Parent.Evaluate(sF1)
End If
If CFColorindex Then
If text Then
If Not IsNull(oFC.Font.ColorIndex) Then
CFColorindex = oFC.Font.ColorIndex
End If
Else
If Not IsNull(oFC.Interior.ColorIndex) Then
CFColorindex = oFC.Interior.ColorIndex
End If
End If
Exit Function
End If
Next oFC
End If 'rng.FormatConditions.Count > 0
End Function
Public Function CFColorCount(rng As Range, _
ciValue, _
Optional text As Boolean = False)
Dim cell As Range, row As Range
Dim i As Long, j As Long
Dim aryColours As Variant
If rng.Areas.Count > 1 Then
CFColorCount = "#Too many areas!"
Exit Function
End If
If rng.Cells.Count = 1 Then
CFColorCount = -CLng(CFColorindex(rng, text) = ciValue)
Else
i = 0
For Each row In rng.Rows
i = i + 1
j = 0
For Each cell In row.Cells
j = j + 1
CFColorCount = CFColorCount - CLng(CFColorindex(cell, text) = ciValue)
Next cell
Next row
End If
End Function