Code not working

KasperC

New Member
Joined
May 11, 2023
Messages
49
Office Version
  1. 365
Platform
  1. Windows
  2. MacOS
Hello,

I'm trying to delete some rows from my data-set depending on what values certain cells contains (see code below).
It works fine if the cell is 3, the macro returns the correct values - but for the rest of the cases, the rows won't delete.
(for the reccord, I don't know for certain if the rows are deleting for the case 3, and not value 133 or 148 statement)

VBA Code:
    LastRow = ws.Cells(Rows.Count, 1).End(xlUp).Row
    Dim y As Integer
        For y = 2 To LastRow
            Select Case ws.Cells(y, 2)
                Case "0", "1", "4", "8", "9", "53"
                    ws.Cells(y, 2).EntireRow.Delete Shift:=xlUp
                Case "3"
                    If ws.Cells(y, 6).Value = "133" Or ws.Cells(y, 6).Value = "148" Then
                            ws.Cells(y, 2) = "J3"
                        Else
                            If ws.Cells(y, 6).Value = "139" Or ws.Cells(y, 6).Value = "354" Then
                                    ws.Cells(y, 2) = "JC"
                                Else
                                    ws.Cells(y, 2).EntireRow.Delete Shift:=xlUp
                                End If
                        End If
            End Select
        Next y

Any suggestions?

Best Regards,
Kasper

Edit* sorry for the short title, wrote it as a temporary title but forgot to change it before posting. Cant seem to change the title after posting
 

Excel Facts

What does custom number format of ;;; mean?
Three semi-colons will hide the value in the cell. Although most people use white font instead.
Issiue fixed - saw I was working through the rows in the wrong direction.

Fixed with "For y = LastRow To 2 Step -1"
 
Upvote 0
Solution

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