Can I combine randbetween, rept, and vlookup to get multiple answers?

Marla89

New Member
Joined
Apr 15, 2024
Messages
3
Office Version
  1. 365
Platform
  1. Windows
  2. Mobile
I am trying to create a formula that will generate a random number of answers from a table and return it as one combined answer.
I thought something like this might work:
=REPT(VLOOKUP(RANDBETWEEN(1,5),A1:B5,FALSE()),RANDBETWEEN(1,3))
The Idea is I have a table with 2 columns and 5 rows. I want to randomly generate a number for column A for vlookup to pull for column B. Than I want to repeat this equation a random number of times between 1 and 3. So that when the formula is complete I will have 1 to 3 randomly generated answers from the 5 rows in column B.
Example:
Column A reads 1 in cell A1, 2 in cell A2, ect.
Column B reads A in cell1B, B in cell 2B, ect.
So in cell 1C, where I would input the formula, I get an answer like: D, A, B
The formula I posted at the top was my best guess. It currently returns an error message of #VALUE!
I'm not sure if I'm misusing the formula or not, or if there is a better one to use.
Column B will end of having phrases in each cell, if that makes a difference.
 

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Book1
ABC
11AC, A, B
22B
33C
44D
55E
6
Sheet2
Cell Formulas
RangeFormula
A1:A5A1=SEQUENCE(5)
C1C1=TEXTJOIN(", ",1,TAKE(SORTBY(B1:B5,RANDARRAY(5)),RANDBETWEEN(1,3)))
Dynamic array formulas.
 
Upvote 0
@JGordon11
I see how that can work, but I do need to use column A as the reference rather than randomizing from column B.
 
Upvote 0
Why? That would require a longer and more complicated formula to get the same result.
Because some of the tables I would like to apply the formula to require me to randomly generate a number from column A and than add 20 (as an example, this number changes sometimes or isn't there at all) to it. So unless I could add on to your equation to tell it to go 20, ect., cells further down in column B for one or more of the options. I'm not sure how to get away from using column A
 
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