Calculating permutations by grouping and then listing them all together in one column

Hawk11ns

Board Regular
Joined
Jul 21, 2015
Messages
61
Office Version
  1. 365
Platform
  1. Windows
Hello everyone, I have been using the below macro to calculate the number of permutations (output columns C onward) for a list (input column A) based on the number chosen (input column B). However, I now have a list that is further broken down by groupings. My goal is to be able to input this list into Column A with the corresponding group number in column B, input the number chosen in column c, and have the permutation output for each group listed all together in column C onwards. The permutations need to be calculated at the group level, meaning that items in group 1 should not be permuted against those in any other group. As always, any and all advice is appreciated. Thanks!

Below is the example output I am looking for.

[TABLE="width: 440"]
<tbody>[TR]
[TD][/TD]
[TD][/TD]
[TD="colspan: 2"] List of Permutations
[/TD]
[/TR]
[TR]
[TD]Name
[/TD]
[TD]Group
[/TD]
[TD]Employee A
[/TD]
[TD]Employee B
[/TD]
[/TR]
[TR]
[TD]Bob
[/TD]
[TD]1
[/TD]
[TD]Bob
[/TD]
[TD]Ginger
[/TD]
[/TR]
[TR]
[TD]Ginger
[/TD]
[TD]1
[/TD]
[TD]Ginger
[/TD]
[TD]Bob
[/TD]
[/TR]
[TR]
[TD]Tommy
[/TD]
[TD]2
[/TD]
[TD]Tommy
[/TD]
[TD]Dave
[/TD]
[/TR]
[TR]
[TD]Dave
[/TD]
[TD]2
[/TD]
[TD]Dave
[/TD]
[TD]Tommy
[/TD]
[/TR]
[TR]
[TD]Wendy
[/TD]
[TD]3
[/TD]
[TD]Wendy
[/TD]
[TD]Trisha
[/TD]
[/TR]
[TR]
[TD]Trisha
[/TD]
[TD]3
[/TD]
[TD]Wendy
[/TD]
[TD]Cindy
[/TD]
[/TR]
[TR]
[TD]Cindy
[/TD]
[TD]3
[/TD]
[TD]Wendy
[/TD]
[TD]Robert
[/TD]
[/TR]
[TR]
[TD]Robert
[/TD]
[TD]3
[/TD]
[TD]Trisha
[/TD]
[TD]Wendy
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Trisha
[/TD]
[TD]Cindy
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Trisha
[/TD]
[TD]Robert
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Cindy
[/TD]
[TD]Wendy
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Cindy
[/TD]
[TD]Trisha
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Cindy
[/TD]
[TD]Robert
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Robert
[/TD]
[TD]Wendy
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Robert
[/TD]
[TD]Trisha
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Robert
[/TD]
[TD]Cindy
[/TD]
[/TR]
</tbody>[/TABLE]



Code:
Sub Permutations()
Dim rRng As Range, p
Dim vElements, lRow As Long, vresult As Variant
 
Set rRng = Range("A1", Range("A1").End(xlDown)) ' The set of values
p = Range("B1").Value ' How many are picked
 
vElements = Application.Index(Application.Transpose(rRng), 1, 0)
ReDim vresult(1 To p)
Application.ScreenUpdating = False
Call PermutationsNP(vElements, CInt(p), vresult, lRow, 1)
Application.ScreenUpdating = True
End Sub
 
Sub PermutationsNP(vElements As Variant, p As Integer, vresult As Variant, lRow As Long, iIndex As Integer)
Dim i As Long, j As Long, bSkip As Boolean
 
For i = 1 To UBound(vElements)
    bSkip = False
    For j = 1 To iIndex - 1
        If vresult(j) = vElements(i) Then
            bSkip = True
            Exit For
        End If
    Next j
    If Not bSkip Then
        vresult(iIndex) = vElements(i)
        If iIndex = p Then
            lRow = lRow + 1
            Range("C" & lRow).Resize(, p) = vresult
        Else
            Call PermutationsNP(vElements, p, vresult, lRow, iIndex + 1)
        End If
    End If
Next i
End Sub
 

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Try this:-
Results start column "C"
Code:
Option Explicit
Dim lrow As Long
Sub perm()
Dim rng As Range, Dn As Range, n As Long, K As Variant
Set rng = Range("B2", Range("B" & Rows.Count).End(xlUp))
With CreateObject("scripting.dictionary")
.CompareMode = vbTextCompare
For Each Dn In rng
    If Not .Exists(Dn.Value) Then
        .Add Dn.Value, Dn.Offset(, -1)
    Else
        Set .Item(Dn.Value) = Union(.Item(Dn.Value), Dn.Offset(, -1))
    End If
Next
For Each K In .keys
    Call Permutations(.Item(K))
Next K
End With
End Sub
Sub Permutations(rng)
Dim rRng As Range, p
Dim vElements, vresult As Variant
 Set rRng = rng
p = 2
If Not lrow = 0 Then lrow = lrow + 1
vElements = Application.Index(Application.Transpose(rRng), 1, 0)
ReDim vresult(1 To p)
Application.ScreenUpdating = False
Call PermutationsNP(vElements, CInt(p), vresult, lrow, 1)
Application.ScreenUpdating = True
End Sub
 
Sub PermutationsNP(vElements As Variant, p As Integer, vresult As Variant, lrow As Long, iIndex As Integer)
Dim i As Long, j As Long, bSkip As Boolean
 
For i = 1 To UBound(vElements)
    bSkip = False
    For j = 1 To iIndex - 1
        If vresult(j) = vElements(i) Then
            bSkip = True
            Exit For
        End If
    Next j
    If Not bSkip Then
        vresult(iIndex) = vElements(i)
        If iIndex = p Then
            lrow = lrow + 1
            Range("C" & lrow).Resize(, p) = vresult
        Else
            
            Call PermutationsNP(vElements, p, vresult, lrow, iIndex + 1)
        End If
    End If
Next i
End Sub
 
Upvote 0
Thanks but I receive a 'Type Mismatch' error. When I step into debug mode, it takes me to this specific line:

For i = 1 To UBound(vElements)
 
Upvote 0

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