Calculate Length of Experience

aasher1

New Member
Joined
Jan 25, 2017
Messages
9
[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD][/TD]
[TD]Start Date
[/TD]
[TD]End Date
[/TD]
[TD]Experience
[/TD]
[/TR]
[TR]
[TD]Job 1
[/TD]
[TD]04/04/89
[/TD]
[TD]09/30/97
[/TD]
[TD]8 years, 5 months, 26 days
[/TD]
[/TR]
[TR]
[TD]Job 2
[/TD]
[TD]06/16/97
[/TD]
[TD]06/27/97
[/TD]
[TD]11 days
[/TD]
[/TR]
[TR]
[TD]Job 3
[/TD]
[TD]07/07/97
[/TD]
[TD]06/24/16
[/TD]
[TD]18 years, 11 months, 17 days
[/TD]
[/TR]
[TR]
[TD]Job 5
[/TD]
[TD]06/27/16
[/TD]
[TD]01/03/19
[/TD]
[TD]2 years, 6 months, 6 days
[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]Total
[/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

I would like to be able to calculate the total number of years, months, and days experience a person has from individual jobs. I have the DATEDIF function to calculate the time elapsed between dates for each job, but can't figure out how to get them to add together.

Thank you.
 

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You could figure out the total duration using

=(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5)

Then use your DATEDIF formula using 0 as the start date, and that amount as the end date.
 
Upvote 0
That's a pretty strange way to show experience.

Q: Which is longer, 1 month and 1 day, or 30 days?

A: It depends.

Why not just ...

[Table="width:, class:grid"][tr][td="bgcolor:#C0C0C0"][/td][td="bgcolor:#C0C0C0"]
A​
[/td][td="bgcolor:#C0C0C0"]
B​
[/td][td="bgcolor:#C0C0C0"]
C​
[/td][td="bgcolor:#C0C0C0"]
D​
[/td][td="bgcolor:#C0C0C0"]
E​
[/td][/tr][tr][td="bgcolor:#C0C0C0"]
1​
[/td][td="bgcolor:#F3F3F3"]
Job
[/td][td="bgcolor:#F3F3F3"]
Start Date
[/td][td="bgcolor:#F3F3F3"]
End Date
[/td][td="bgcolor:#F3F3F3"]
Experience [yrs]
[/td][td][/td][/tr]
[tr][td="bgcolor:#C0C0C0"]
2​
[/td][td]Job 1[/td][td]
4/4/1989​
[/td][td]
9/30/1997​
[/td][td]
8.49​
[/td][td]D2: =(C2-B2)/365.25[/td][/tr]
[tr][td="bgcolor:#C0C0C0"]
3​
[/td][td]Job 2[/td][td]
6/16/1997​
[/td][td]
6/27/1997​
[/td][td]
0.03​
[/td][td][/td][/tr]
[tr][td="bgcolor:#C0C0C0"]
4​
[/td][td]Job 3[/td][td]
7/7/1997​
[/td][td]
6/24/2016​
[/td][td]
18.97​
[/td][td][/td][/tr]
[tr][td="bgcolor:#C0C0C0"]
5​
[/td][td]Job 5[/td][td]
6/27/2016​
[/td][td]
1/3/2019​
[/td][td]
2.52​
[/td][td][/td][/tr]
[tr][td="bgcolor:#C0C0C0"]
6​
[/td][td="bgcolor:#F3F3F3"]
Total
[/td][td][/td][td][/td][td]
30.0​
[/td][td]D6: =SUM(D2:D5)[/td][/tr]
[/table]
 
Upvote 0
Thank you so much Eric W. It's always easier then what I try do.This is what I did.

=IF(DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"y")=0,"",DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"y")&"years,")&IF(DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"ym")=0,"",DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"ym")&"months, ")& IF(DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"md")=0,"",DATEDIF(0,(C2-B2)+(C3-B3)+(C4-B4)+(C5-B5),"md")&"days")


I thought it funny though, if using last date of 01/02/19 it gives me “29 years,11 months, 31 days” instead of just 30 years. Then using the last date of 01/03/19 it gives me “30 years, 1 days”
 
Last edited:
Upvote 0
First, here's a slightly shorter version of the formula:

=SUMPRODUCT(C2:C5-B2:B5)

Next, I've seen similar DATEDIF formulas to get the years/months/days. I'm not going to worry about why it generates "31 days" as part of it. After all, after 30 years, does it really matter if it's plus or minus a day or two? I think shg's approach has a lot of validity to it.

In any case, I'm glad we could help.
 
Upvote 0

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