Bypassing An Error associated with failed vlookup

Ark68

Well-known Member
Joined
Mar 23, 2004
Messages
4,564
Office Version
  1. 365
  2. 2016
Platform
  1. Windows
I have this code:

Code:
With uf9_poststaff
            .cu2_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu2_en.Value), rg_staff, 5, False), "hh:mm")
            .cu2_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu2_en.Value), rg_staff, 6, False), "h:mm")
            .cu2_hours.Value = format(DateDiff("h", .cu2_end.Value, .cu2_start.Value) / 24, "standard")
            
            .cu3_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu3_en.Value), rg_staff, 5, False), "hh:mm")
            .cu3_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu3_en.Value), rg_staff, 6, False), "h:mm")
            .cu3_hours.Value = format(DateDiff("h", .cu3_end.Value, .cu3_start.Value) / 24, "standard")
            
            .wprk1_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.wprk1_en.Value), rg_staff, 5, False), "hh:mm")
            .wprk1_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.wprk1_en.Value), rg_staff, 6, False), "h:mm")
            .wprk1_hours.Value = format(DateDiff("h", .wprk1_end.Value, .wprk1_start.Value) / 24, "standard")
            
            .wbvd1_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.wbvd1_en.Value), rg_staff, 5, False), "hh:mm")
            .wbvd1_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.wbvd1_en.Value), rg_staff, 6, False), "h:mm")
            .wbvd1_hours.Value = format(DateDiff("h", .wbvd1_end.Value, .wbvd1_start.Value) / 24, "standard")
            
            .cu4_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu4_en.Value), rg_staff, 5, False), "hh:mm")
            .cu4_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu4_en.Value), rg_staff, 6, False), "h:mm")
            .cu4_hours.Value = format(DateDiff("h", .cu4_end.Value, .cu4_start.Value) / 24, "standard")
            
            .cu5_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu5_en.Value), rg_staff, 5, False), "hh:mm")
            .cu5_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu5_en.Value), rg_staff, 6, False), "h:mm")
            .cu5_hours.Value = format(DateDiff("h", .cu5_end.Value, .cu5_start.Value) / 24, "standard")
            
            .cu6_start.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu6_en.Value), rg_staff, 5, False), "hh:mm")
            .cu6_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu6_en.Value), rg_staff, 6, False), "h:mm")
            .cu6_hours.Value = format(DateDiff("h", .cu6_end.Value, .cu6_start.Value) / 24, "standard")
            
        End With

Any on e or more line may error when the vlookup fails to find the lookup value.
What kind of error checking code could I use to ignore the error associated with an inability to match and just simply move to the next line?
 

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I adapted my code as an experiment ... as an example

Rich (BB code):
            .cu5_start.Value = format(Application.VLookup(CLng(.cu5_en.Value), rg_staff, 5, False), "hh:mm")
            If IsError(.cu5_start.Value) Then
                MsgBox "no match"
            Else
                .cu5_end.Value = format(Application.WorksheetFunction.VLookup(CLng(.cu5_en.Value), rg_staff, 6, False), "h:mm")
                .cu5_hours.Value = format(DateDiff("h", .cu5_end.Value, .cu5_start.Value) / 24, "standard")
            End If

But this leaves me with a "type mismatch" error with the line in red.
 
Upvote 0
Maybe:
Rich (BB code):
On Error Resume Next
.cu5_start.Value = Format(Application.VLookup(CLng(.cu5_en.Value), rg_staff, 5, False), "hh:mm")
            If IsError(.cu5_start.Value) Then
                MsgBox "no match"
                On Error GoTo 0
            Else
                .cu5_end.Value = Format(Application.WorksheetFunction.VLookup(CLng(.cu5_en.Value), rg_staff, 6, False), "h:mm")
                .cu5_hours.Value = Format(DateDiff("h", .cu5_end.Value, .cu5_start.Value) / 24, "standard")
            End If
 
Upvote 0

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