Breakdown data in groups by relation

R

Razr

New Member
Joined
Jan 13, 2009
Messages
35
Hello everybody,

I have a quite large data sets (70.000) and would like your help.

Data sets looks as follows:


[TABLE="width: 128"]
<colgroup><col width="64" span="2" style="width:48pt"> </colgroup><tbody>[TR]
[TD="width: 64"]COL1
(orderid)[/TD]
[TD="width: 64"]COL2 (prod.id)[/TD]
[/TR]
[TR]
[TD="class: xl65"]group1[/TD]
[TD="class: xl65, align: right"]230[/TD]
[/TR]
[TR]
[TD="class: xl65"]group1[/TD]
[TD="class: xl65, align: right"]501[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]1231[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]501[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]2141[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]5151[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]51591[/TD]
[/TR]
[TR]
[TD="class: xl65"]group2[/TD]
[TD="class: xl65, align: right"]212312[/TD]
[/TR]
[TR]
[TD="class: xl65"]group3[/TD]
[TD="class: xl65, align: right"]230[/TD]
[/TR]
[TR]
[TD="class: xl65"]group3[/TD]
[TD="class: xl65, align: right"]25151[/TD]
[/TR]
[TR]
[TD="class: xl65"]group3[/TD]
[TD="class: xl65, align: right"]24515[/TD]
[/TR]
[TR]
[TD="class: xl65"]group3[/TD]
[TD="class: xl65, align: right"]5122591[/TD]
[/TR]
[TR]
[TD="class: xl65"]group4[/TD]
[TD="class: xl65, align: right"]2255[/TD]
[/TR]
[TR]
[TD="class: xl65"]group4[/TD]
[TD="class: xl65, align: right"]501[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]25151[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]55[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]1241[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]151[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]51521[/TD]
[/TR]
[TR]
[TD="class: xl65"]group5[/TD]
[TD="class: xl65, align: right"]25252[/TD]
[/TR]
</tbody>[/TABLE]
....... .........

What I want to do is regroup these groups based on relation.

For example 230 exists in Group 1 & Group 3
So we have one group there which consists of all which means

230,501,230,25151,24515,5122591.

But then 501 also coexists in group 4 so our group gets bigger we need to add also 2255 to our set

230,501,230,25151,24515,5122591,2255

But then 2255 also exists in group *** so we need to add *** since it coexists with 2255

So basically I need to make a group breakdown of all products that exist in same orderids.

In other words I need to group data by relation.
In a more "logical" language imagine this as "related products" group breakdown (where the criteria is that they coexist in any give orderid).

I hope this is clear.

Thank you in advance
 

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Try this for Results starting "D1".
Code: 
[COLOR="Navy"]Sub[/COLOR] MG26Mar44
[COLOR="Navy"]Dim[/COLOR] Dic [COLOR="Navy"]As[/COLOR] Object, Dic2 [COLOR="Navy"]As[/COLOR] Object, Dic3 [COLOR="Navy"]As[/COLOR] Object
[COLOR="Navy"]Dim[/COLOR] Rng [COLOR="Navy"]As[/COLOR] Range, Dn [COLOR="Navy"]As[/COLOR] Range, N [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long[/COLOR]
[COLOR="Navy"]Set[/COLOR] Rng = Range("b2", Range("b" & Rows.Count).End(xlUp))
[COLOR="Navy"]Set[/COLOR] Dic = CreateObject("scripting.dictionary")
Dic.CompareMode = vbTextCompare
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng
    [COLOR="Navy"]If[/COLOR] Not Dic.Exists(Dn.Value) [COLOR="Navy"]Then[/COLOR]
        Dic.Add Dn.Value, Dn.Offset(, -1).Value
    [COLOR="Navy"]Else[/COLOR]
        Dic(Dn.Value) = Dic(Dn.Value) & ", " & Dn.Offset(, -1).Value
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR]
[COLOR="Navy"]Set[/COLOR] Rng = Range("A2", Range("A" & Rows.Count).End(xlUp))
[COLOR="Navy"]Set[/COLOR] Dic2 = CreateObject("scripting.dictionary")
Dic2.CompareMode = vbTextCompare
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng
    [COLOR="Navy"]If[/COLOR] Not Dic2.Exists(Dn.Value) [COLOR="Navy"]Then[/COLOR]
        Dic2.Add Dn.Value, Dn.Offset(, 1).Value
    [COLOR="Navy"]Else[/COLOR]
        Dic2(Dn.Value) = Dic2(Dn.Value) & ", " & Dn.Offset(, 1).Value
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR]
[COLOR="Navy"]Dim[/COLOR] R [COLOR="Navy"]As[/COLOR] Variant, Sp [COLOR="Navy"]As[/COLOR] Variant, nStr [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]String[/COLOR]
[COLOR="Navy"]Set[/COLOR] Dic3 = CreateObject("scripting.dictionary")
Dic3.CompareMode = vbTextCompare
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] R [COLOR="Navy"]In[/COLOR] Dic.items
    Sp = Split(R, ", ")
    nStr = ""
        [COLOR="Navy"]For[/COLOR] N = 0 To UBound(Sp)
            nStr = nStr & IIf(nStr = "", Dic2(Sp(N)), ", " & Dic2(Sp(N)))
        [COLOR="Navy"]Next[/COLOR] N
        [COLOR="Navy"]If[/COLOR] Not Dic3.Exists(R) [COLOR="Navy"]Then[/COLOR]
            Dic3.Add R, nStr
        [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR] R
[COLOR="Navy"]With[/COLOR] Range("D1").Resize(Dic3.Count, 2)
    .Value = Application.Transpose(Array(Dic3.Keys, Dic3.items))
    .Borders.Weight = 2
    .Columns.AutoFit
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]With[/COLOR]
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]Sub[/COLOR]
Regards Mick
 
Upvote 0
MickG said:
Try this for Results starting "D1".
Code: 
[COLOR=Navy]Sub[/COLOR] MG26Mar44
[COLOR=Navy]Dim[/COLOR] Dic [COLOR=Navy]As[/COLOR] Object, Dic2 [COLOR=Navy]As[/COLOR] Object, Dic3 [COLOR=Navy]As[/COLOR] Object
[COLOR=Navy]Dim[/COLOR] Rng [COLOR=Navy]As[/COLOR] Range, Dn [COLOR=Navy]As[/COLOR] Range, N [COLOR=Navy]As[/COLOR] [COLOR=Navy]Long[/COLOR]
[COLOR=Navy]Set[/COLOR] Rng = Range("b2", Range("b" & Rows.Count).End(xlUp))
[COLOR=Navy]Set[/COLOR] Dic = CreateObject("scripting.dictionary")
Dic.CompareMode = vbTextCompare
[COLOR=Navy]For[/COLOR] [COLOR=Navy]Each[/COLOR] Dn [COLOR=Navy]In[/COLOR] Rng
    [COLOR=Navy]If[/COLOR] Not Dic.Exists(Dn.Value) [COLOR=Navy]Then[/COLOR]
        Dic.Add Dn.Value, Dn.Offset(, -1).Value
    [COLOR=Navy]Else[/COLOR]
        Dic(Dn.Value) = Dic(Dn.Value) & ", " & Dn.Offset(, -1).Value
    [COLOR=Navy]End[/COLOR] If
[COLOR=Navy]Next[/COLOR]
[COLOR=Navy]Set[/COLOR] Rng = Range("A2", Range("A" & Rows.Count).End(xlUp))
[COLOR=Navy]Set[/COLOR] Dic2 = CreateObject("scripting.dictionary")
Dic2.CompareMode = vbTextCompare
[COLOR=Navy]For[/COLOR] [COLOR=Navy]Each[/COLOR] Dn [COLOR=Navy]In[/COLOR] Rng
    [COLOR=Navy]If[/COLOR] Not Dic2.Exists(Dn.Value) [COLOR=Navy]Then[/COLOR]
        Dic2.Add Dn.Value, Dn.Offset(, 1).Value
    [COLOR=Navy]Else[/COLOR]
        Dic2(Dn.Value) = Dic2(Dn.Value) & ", " & Dn.Offset(, 1).Value
    [COLOR=Navy]End[/COLOR] If
[COLOR=Navy]Next[/COLOR]
[COLOR=Navy]Dim[/COLOR] R [COLOR=Navy]As[/COLOR] Variant, Sp [COLOR=Navy]As[/COLOR] Variant, nStr [COLOR=Navy]As[/COLOR] [COLOR=Navy]String[/COLOR]
[COLOR=Navy]Set[/COLOR] Dic3 = CreateObject("scripting.dictionary")
Dic3.CompareMode = vbTextCompare
[COLOR=Navy]For[/COLOR] [COLOR=Navy]Each[/COLOR] R [COLOR=Navy]In[/COLOR] Dic.items
    Sp = Split(R, ", ")
    nStr = ""
        [COLOR=Navy]For[/COLOR] N = 0 To UBound(Sp)
            nStr = nStr & IIf(nStr = "", Dic2(Sp(N)), ", " & Dic2(Sp(N)))
        [COLOR=Navy]Next[/COLOR] N
        [COLOR=Navy]If[/COLOR] Not Dic3.Exists(R) [COLOR=Navy]Then[/COLOR]
            Dic3.Add R, nStr
        [COLOR=Navy]End[/COLOR] If
[COLOR=Navy]Next[/COLOR] R
[COLOR=Navy]With[/COLOR] Range("D1").Resize(Dic3.Count, 2)
    .Value = Application.Transpose(Array(Dic3.Keys, Dic3.items))
    .Borders.Weight = 2
    .Columns.AutoFit
[COLOR=Navy]End[/COLOR] [COLOR=Navy]With[/COLOR]
[COLOR=Navy]End[/COLOR] [COLOR=Navy]Sub[/COLOR]
Regards Mick
Click to expand...

Thank you MickG.

Is there any way to get unique values in the results?

I am getting repetitive values in the comma separated results in the prodid result (column E). For example 5122591,5122591

Moreover I am getting same prodID in many rows results I need in one row unique prodIds.
 
Upvote 0
There is no problem getting Unique "prodID" number per row, but as each set of "prodID" number relates to related groups, it seems inevitable that there will be duplicates across all groups.
With that in mind , and the results below what would you like to see as you actual Results.???

[TABLE="width: 401"]
<tbody>[TR]
[TD="class: xl63, width: 144, bgcolor: transparent"]group1, group3
[/TD]
[TD="class: xl63, width: 390, bgcolor: transparent"]230, 501, 230, 25151, 24515, 5122591
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group1, group2, group4
[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 501, 1231, 501, 2141, 5151, 51591, 212312, 2255, 501
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group2
[/TD]
[TD="class: xl63, bgcolor: transparent"]1231, 501, 2141, 5151, 51591, 212312
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group3, group5
[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 25151, 24515, 5122591, 25151, 55, 1241, 151, 51521, 25252
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group3
[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 25151, 24515, 5122591
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group4
[/TD]
[TD="class: xl63, bgcolor: transparent"]2255, 501
[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group5
[/TD]
[TD="class: xl63, bgcolor: transparent"]25151, 55, 1241, 151, 51521, 25252
[/TD]
[/TR]
</tbody>[/TABLE]
 
Last edited:
Upvote 0
MickG said:
There is no problem getting Unique "prodID" number per row, but as each set of "prodID" number relates to related groups, it seems inevitable that there will be duplicates across all groups.
With that in mind , and the results below what would you like to see as you actual Results.???

[TABLE="width: 401"]
<tbody>[TR]
[TD="class: xl63, width: 144, bgcolor: transparent"]group1, group3[/TD]
[TD="class: xl63, width: 390, bgcolor: transparent"]230, 501, 230, 25151, 24515, 5122591[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group1, group2, group4[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 501, 1231, 501, 2141, 5151, 51591, 212312, 2255, 501[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group2[/TD]
[TD="class: xl63, bgcolor: transparent"]1231, 501, 2141, 5151, 51591, 212312[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group3, group5[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 25151, 24515, 5122591, 25151, 55, 1241, 151, 51521, 25252[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group3[/TD]
[TD="class: xl63, bgcolor: transparent"]230, 25151, 24515, 5122591[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group4[/TD]
[TD="class: xl63, bgcolor: transparent"]2255, 501[/TD]
[/TR]
[TR]
[TD="class: xl63, bgcolor: transparent"]group5[/TD]
[TD="class: xl63, bgcolor: transparent"]25151, 55, 1241, 151, 51521, 25252[/TD]
[/TR]
</tbody>[/TABLE]
Click to expand...

Yep that's exactly what i need as actual results
 
Upvote 0
Try this:-
Result start "D1"

Code: 
[COLOR=navy]Sub[/COLOR] MG27Mar41
[COLOR=navy]Dim[/COLOR] Dic [COLOR=navy]As[/COLOR] Object, Dic2 [COLOR=navy]As[/COLOR] Object, Dic3 [COLOR=navy]As[/COLOR] Object
[COLOR=navy]Dim[/COLOR] Rng [COLOR=navy]As[/COLOR] Range, Dn [COLOR=navy]As[/COLOR] Range, n [COLOR=navy]As[/COLOR] [COLOR=navy]Long[/COLOR]
[COLOR=navy]Set[/COLOR] Rng = Range("b2", Range("b" & Rows.Count).End(xlUp))
[COLOR=navy]Set[/COLOR] Dic = CreateObject("scripting.dictionary")
Dic.CompareMode = vbTextCompare
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] Dn [COLOR=navy]In[/COLOR] Rng
    [COLOR=navy]If[/COLOR] Not Dic.Exists(Dn.Value) [COLOR=navy]Then[/COLOR]
        Dic.Add Dn.Value, Dn.Offset(, -1).Value
    [COLOR=navy]Else[/COLOR]
        Dic(Dn.Value) = Dic(Dn.Value) & ", " & Dn.Offset(, -1).Value
    [COLOR=navy]End[/COLOR] If
[COLOR=navy]Next[/COLOR]
[COLOR=navy]Set[/COLOR] Rng = Range("A2", Range("A" & Rows.Count).End(xlUp))
[COLOR=navy]Set[/COLOR] Dic2 = CreateObject("scripting.dictionary")
Dic2.CompareMode = vbTextCompare
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] Dn [COLOR=navy]In[/COLOR] Rng
    [COLOR=navy]If[/COLOR] Not Dic2.Exists(Dn.Value) [COLOR=navy]Then[/COLOR]
        Dic2.Add Dn.Value, Dn.Offset(, 1).Value
    [COLOR=navy]Else[/COLOR]
        Dic2(Dn.Value) = Dic2(Dn.Value) & ", " & Dn.Offset(, 1).Value
    [COLOR=navy]End[/COLOR] If
[COLOR=navy]Next[/COLOR]
[COLOR=navy]Dim[/COLOR] R [COLOR=navy]As[/COLOR] Variant, Sp [COLOR=navy]As[/COLOR] Variant, nStr [COLOR=navy]As[/COLOR] [COLOR=navy]String[/COLOR]
[COLOR=navy]Set[/COLOR] Dic3 = CreateObject("scripting.dictionary")
Dic3.CompareMode = vbTextCompare
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] R [COLOR=navy]In[/COLOR] Dic.items
    Sp = Split(R, ", ")
    nStr = ""
        [COLOR=navy]For[/COLOR] n = 0 To UBound(Sp)
            nStr = nStr & IIf(nStr = "", Dic2(Sp(n)), ", " & Dic2(Sp(n)))
        [COLOR=navy]Next[/COLOR] n
        [COLOR=navy]If[/COLOR] Not Dic3.Exists(R) [COLOR=navy]Then[/COLOR]
            Dic3.Add R, nStr
        [COLOR=navy]End[/COLOR] If
[COLOR=navy]Next[/COLOR] R
[COLOR=navy]Dim[/COLOR] K [COLOR=navy]As[/COLOR] Variant
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] K [COLOR=navy]In[/COLOR] Dic3.keys
    Sp = Split(Dic3(K), ", ")
    nStr = ""
        [COLOR=navy]For[/COLOR] n = 0 To UBound(Sp)
            [COLOR=navy]If[/COLOR] InStr(nStr, Sp(n)) = 0 [COLOR=navy]Then[/COLOR]
                nStr = nStr & IIf(nStr = "", Sp(n), ", " & Sp(n))
            [COLOR=navy]End[/COLOR] If
        [COLOR=navy]Next[/COLOR] n
        Dic3(K) = nStr
[COLOR=navy]Next[/COLOR] K
[COLOR=navy]With[/COLOR] Range("D1").Resize(Dic3.Count, 2)
    .Value = Application.Transpose(Array(Dic3.keys, Dic3.items))
    .Borders.Weight = 2
    .Columns.AutoFit
[COLOR=navy]End[/COLOR] [COLOR=navy]With[/COLOR]
[COLOR=navy]End[/COLOR] [COLOR=navy]Sub[/COLOR]
Regards Mick
 
Last edited:
Upvote 0
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