Assign a number of occurrence to each record (sort of Count if)

TamirBasin

New Member
Joined
Apr 11, 2017
Messages
49
Office Version
  1. 365
Platform
  1. Windows
Hi,
How can I achieve the same calculation in Power Query?
In Excel I would use: =COUNTIF($A$2:A2,A2)

NameOccurrence
A1
A2
B1
A3
B2

<tbody>
[TD="colspan: 2"][/TD]

</tbody>


Regards,
Tamir
 

Excel Facts

Why does 9 mean SUM in SUBTOTAL?
It is because Sum is the 9th alphabetically in Average, Count, CountA, Max, Min, Product, StDev.S, StDev.P, Sum, VAR.S, VAR.P.
Here's what I did:
• I made your sample data a table named Table1
• Added that table to Power Query (as a query named SourceData)
• Created this query to assign the clustered indexes:
Code:
let
    Source = SourceData,
    InsertedIndex = Table.AddIndexColumn(Source,"Index"),
    AddGroupingTableToEachRows = Table.Group(InsertedIndex, {"Name"}, {{"Values", each _, type table}}),
    AddIndexToEachGroupedTable = Table.TransformColumns(AddGroupingTableToEachRows,{{"Values", each Table.AddIndexColumn(Table.Sort(_, "Index"),"GroupIndex",1)}}),
    ExposeCols = Table.ExpandTableColumn(AddIndexToEachGroupedTable, "Values", {"Index", "GroupIndex"}, {"Index", "GroupIndex"}),
    MergeIndexedDataWithGroupedIndex = Table.NestedJoin(InsertedIndex,{"Index"},ExposeCols,{"Index"},"NewColumn",JoinKind.LeftOuter),
    ExposeGroupIndexCol = Table.ExpandTableColumn(MergeIndexedDataWithGroupedIndex, "NewColumn", {"GroupIndex"}, {"GroupIndex"}),
    SortedIntoOrigOrder = Table.Sort(ExposeGroupIndexCol,{{"Index", Order.Ascending}})
in
    SortedIntoOrigOrder
• These are the results:
[TABLE="width: 190"]
<tbody>[TR]
[TD]Name
[/TD]
[TD]Index
[/TD]
[TD]GroupIndex
[/TD]
[/TR]
[TR]
[TD]A
[/TD]
[TD="align: right"][/TD]
[TD="align: right"]1
[/TD]
[/TR]
[TR]
[TD]A
[/TD]
[TD="align: right"]1
[/TD]
[TD="align: right"]2
[/TD]
[/TR]
[TR]
[TD]B
[/TD]
[TD="align: right"]2
[/TD]
[TD="align: right"]1
[/TD]
[/TR]
[TR]
[TD]A
[/TD]
[TD="align: right"]3
[/TD]
[TD="align: right"]3
[/TD]
[/TR]
[TR]
[TD]B
[/TD]
[TD="align: right"]4
[/TD]
[TD="align: right"]2
[/TD]
[/TR]
</tbody>[/TABLE]

Is that something you can work with?
 
Upvote 0
Thanks Ron,

The code seems to be exactly what I need.

I will try and work it out.

Could you provide some more explanations?

Regards,
Tamir


 
Upvote 0
This one:

Code:
AddIndexToEachGroupedTable = Table.TransformColumns(AddGroupingTableToEachRows,{{"Values", each Table.AddIndexColumn(Table.Sort(_, "Index"),"GroupIndex",1)}}),
 
Upvote 0
It might be easier if you look at what's happening via the edit window.
At the AddGroupingTableToEachRows step....click on one of the "Table" cells. You'll see that it contains all of the records for the specific Name...and it's position in the original listing.
Next, click on the AddIndexToEachGroupedTable step and click on the same "Table" cell. It now contains the Name, original position...and an incremental ordinal! That's the value we really want.

In the following steps we reference the InsertedIndex data and merged our new seq num table and sort the data into its original order.
Does that help?
 
Upvote 0

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