Array formula help

mattri

New Member
Joined
May 9, 2018
Messages
2
Hi,

I'm hoping someone can help with first attempt at an array formula. I have a bank statement in the form:

[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD]Index[/TD]
[TD]Date[/TD]
[TD]Balance[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]05/01/2018[/TD]
[TD]100[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]07/01/2018[/TD]
[TD]150[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]07/01/2018[/TD]
[TD]142[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]07/01/2018[/TD]
[TD]145[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]09/01/2018[/TD]
[TD]500[/TD]
[/TR]
</tbody>[/TABLE]

I would like to be able to type a date into a cell and be provided with a Balance for the same, or nearest previous date, with the largest index value if there are duplicates of the same date. e.g. if I typed 08/01/2018 I would like to get the result 145. I would want the same result if I typed 07/01/2018.

I have managed to get the date index using a helpful array formula from this site, but it is returning the balance for the first matching date in the list. I am unsure how to add the extra criteria to then choose the largest Index out of the matching dates.
{=INDEX(C2:C6,MATCH(MAX(IF((B2:B6<=CHOSENDATE),B2:B6)),B2:B6,0))}

Many thanks in advance.
 

Excel Facts

Using Function Arguments with nested formulas
If writing INDEX in Func. Arguments, type MATCH(. Use the mouse to click inside MATCH in the formula bar. Dialog switches to MATCH.
Welcome to the forum!

How about:

=LOOKUP(2,1/(B2:B6<=CHOSENDATE),C2:C6)

assuming the indexes are in ascending order?
 
Upvote 0
Welcome to the forum!

How about:

=LOOKUP(2,1/(B2:B6<=CHOSENDATE),C2:C6)

assuming the indexes are in ascending order?

Eric

That works brilliantly and seems so simple, yet my brain hurts trying to understand it!

If there were a solution that didn't need the indexes in order then that would be helpful, but it's not essential and this will do the trick.

Many thanks.
 
Upvote 0

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