Add one year to Leap Year

zinzah

New Member
Joined
Mar 9, 2010
Messages
49
Hi all,

Been a while...

Thought i had it figured out, but discovered that Excel Worksheet formula and Excel VBA do not seem to calculate one year from a leap day the same.
In a spreadhseet, i have :
1682537554324.png

Which, in my mind, is correct and the value i want.
However, when using the following formula in a UserForm control:

1682537636804.png

the result is "02/28/2025"

I have tried a number of variations but cannot seem to get VBA to return 3/1/2025.

I need to stay away from adding 365/366 days or "add one year plus one day"...

Any thoughts on why they work differently? and a possible solution?

Chris
 

Excel Facts

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i can't tell you the specifics of how date math works in excel.
But, I've usually always subtracted the day of the month less one to get to the first of the month and then do all my math after that.
so to get March 1 of 2025 from 2/2/29 i would do something like:

VBA Code:
Dim date1 As Date
Dim date2 As Date
date1 = DateSerial(2024, 2, 29)
date2 = DateAdd("m", 13, date1 - Day(date1) + 1)
MsgBox date1 & vbCrLf & date2
 
Upvote 1
Here is another way I got it to work:
VBA Code:
Sub DateTest()

    Dim dte As Date
    Dim dte2 As Date
    
'   Set initial date
    dte = DateSerial(2024, 2, 29)
     
'   Build new date 12 months from first date
    dte2 = DateSerial(Year(dte), Month(dte) + 12, Day(dte))
    
'   Show value
    MsgBox Format(dte2, "MM/DD/YYYY")
    
End Sub
 
Upvote 1
Solution
Here is another way I got it to work:
VBA Code:
Sub DateTest()

    Dim dte As Date
    Dim dte2 As Date
   
'   Set initial date
    dte = DateSerial(2024, 2, 29)
    
'   Build new date 12 months from first date
    dte2 = DateSerial(Year(dte), Month(dte) + 12, Day(dte))
   
'   Show value
    MsgBox Format(dte2, "MM/DD/YYYY")
   
End Sub


Much cleaner and easier to understand @Joe4 ! A bit more typing and clarity is often worth it!
 
Upvote 0
@Joe4 @awoohaw

WooHoo!!!

Made some modifications to @Joe4 code for testing purposes...

VBA Code:
Sub DateTest()

Dim dte As Date
Dim dte2 As Date
  
For i = 1 To 1000
'   Set initial date
    'dte = DateSerial(2024, 2, 29)
    dte = Format(DateSerial(Year(Worksheets("sheet1").Range("a" & i).Value), Month(Worksheets("sheet1").Range("a" & i).Value), Day(Worksheets("sheet1").Range("a" & i).Value)))
'   Build new date 12 months from first date
    dte2 = DateSerial(Year(dte), Month(dte) + 12, Day(dte))
    Worksheets("sheet1").Range("B" & i) = dte2
Next i

and the all important results:
1682555528742.png


Thank you both for the fast replies and awesome solutions!
 
Upvote 0
That is great! I'm pleased you found a solution.

Best Wishes!
 
Upvote 1
Or, you can use VBA to put formula into B1:B1000, then get value, like this:
PHP:
With Range("B1:B1000")
    .Formula = "=DATE(YEAR(A1)+1,MONTH(A1),DAY(A1))"
    .Value = .Value
End With
or, looping from B1:B1000:
use one of the 4 lines inside for...loop
PHP:
For i = 1 To 10000
    'Range("B" & i).Formula = "=DATE(YEAR(A" & i & " )+1,MONTH(A" & i & "),DAY(A" & i & "))"
 'or
    'Range("B" & i).Formula = "=DATE(YEAR(A" & i & " ),MONTH(A" & i & ")+12,DAY(A" & i & "))"
'or
    'Range("B" & i).Value = Evaluate("=DATE(YEAR(A" & i & " )+1,MONTH(A" & i & "),DAY(A" & i & "))")
'or
    'Range("B" & i).Value = Evaluate("=DATE(YEAR(A" & i & " ),MONTH(A" & i & ")+12,DAY(A" & i & "))")
Next
 
Upvote 1
@

@bebo021999

Haha! Thanks for the alternatives...but the loop was strictly for testing. Needed to make sure that 2/28/2023 went out 365 days and then from March 1, 2023 thru February 29, 2024 was 366 , especially with February 29, 2024 going out until March 1, 2025.
 
Upvote 0
Glad we were able to help!
 
Upvote 1

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