Add contributing %s to max 100% total

halesowenmum

Active Member
Joined
Oct 20, 2010
Messages
383
Office Version
  1. 365
Platform
  1. Windows
Hi.

I have a spreadsheet

[TABLE="class: grid, width: 300, align: left"]
<tbody>[TR]
[TD][/TD]
[TD]D[/TD]
[TD]E[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Question 1[/TD]
[TD]90%[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]Q1 assessment criteria 1[/TD]
[TD]20%[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]
Q1 assessment criteria 2
[/TD]
[TD]30%[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]
Q1 assessment criteria 2
[/TD]
[TD]40%[/TD]
[/TR]
</tbody>[/TABLE]









Under Question 1 there are three things users have to report on their progress with. They type in the % figure and CF produces a horizontal progress bar. As we can see it's all hunky dory here as 40 30 and 20 does indeed equate to 90%.

I think it's when the numbers go over what would add up to 100 that we get into trouble.

What about when all three have gotten 80% of the way through - the value in E1 would be 240%, if they all mark that they've finished by typing in '100' the total will show as 300% - which is not what we need.

How do I write the formula in E1 that allows people to put in their progress as described - which is a requirement, but then the total in the E1 would be a cumulative total of their contribution towards the overall goal of reaching 100% ie all sub-tasks completed = 100%.

Can anybody help me with this (quite garbled) explanation I've provided?! :laugh:
 
Last edited:

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Office 365 customers have access to Waterfall charts since late 2016. They were added to Excel 2019.
Is there a way of automating the /3 number part?

what I mean is, there could be a differing number of elements - it might be three contributing scores, it could be 23 - is there a way for the formula to say 'sum the value immediately below this cell and everything up to the row where Col D contains a bold heading then divide the sum of those values divided by the number of values' - because otherwise you'd be having to count and manually adjust each formula on each heading row.
 
Last edited:
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