Access calculation the time difference days and hours

dhen21dx

Board Regular
Joined
May 10, 2013
Messages
166
Hello,

I have saw codes from some forums about calculation of days, however i think it didn't involve the number of hours. Can somebody how the hours will be inserted to calculate the difference.

Thanks


VBA Code:
Public Function ISO_WorkdayDiff( _
  ByVal datDateFrom As Date, _
  ByVal datDateTo As Date, _
  Optional ByVal booExcludeHolidays As Boolean) _
  As Long
'#39; Purpose: Calculate number of working days between dates datDateFrom and datDateTo.
' Assumes: 5 or 6 working days per week. Weekend is (Saturday and) Sunday.
' May be freely used and distributed.
' 1999-04-23. Gustav Brock, Cactus Data ApS, Copenhagen
' 2000-10-03. Constants added.
'             Option for 5 or 6 working days per week added.
' 2008-06-12. Option to exclude holidays from the count of workdays.
  Const cbytWorkdaysOfWeek  As Byte = 5
  ' Name of table with holidays.
  Const cstrTableHoliday    As String = "tblHolidays"
  ' Name of date field in holiday table.
  Const cstrFieldHoliday    As String = "HolidayDate"
  Dim bytSunday             As Byte
  Dim intWeekdayDateFrom    As Integer
  Dim intWeekdayDateTo      As Integer
  Dim lngDays               As Long
  Dim datDateTemp           As Date
  Dim strDateFrom           As String
  Dim strDateTo             As String
  Dim lngHolidays           As Long
  Dim strFilter             As String
  
  ' Reverse dates if these have been input reversed.
  If datDateFrom > datDateTo Then
    datDateTemp = datDateFrom
    datDateFrom = datDateTo
    datDateTo = datDateTemp
  End If
  
  ' Find ISO weekday for Sunday.
  bytSunday = Weekday(vbSunday, vbMonday)
  
  ' Find weekdays for the dates.
  intWeekdayDateFrom = Weekday(datDateFrom, vbMonday)
  intWeekdayDateTo = Weekday(datDateTo, vbMonday)
  
  ' Compensate weekdays' value for non-working days (weekends).
  intWeekdayDateFrom = intWeekdayDateFrom + (intWeekdayDateFrom = bytSunday)
  intWeekdayDateTo = intWeekdayDateTo + (intWeekdayDateTo = bytSunday)
  
  ' Calculate number of working days between the two weekdays, ignoring number of weeks.
  lngDays = intWeekdayDateTo - intWeekdayDateFrom - (cbytWorkdaysOfWeek * (intWeekdayDateTo < intWeekdayDateFrom))
  ' Add number of working days between the weeks of the two dates.
  lngDays = lngDays + (cbytWorkdaysOfWeek * DateDiff("w", datDateFrom, datDateTo, vbMonday, vbFirstFourDays))
  
  If booExcludeHolidays And lngDays > 0 Then
    strDateFrom = Format(datDateFrom, "yyyy\/mm\/dd")
    strDateTo = Format(datDateTo, "yyyy\/mm\/dd")
    strFilter = cstrFieldHoliday & " Between #" & strDateFrom & "# And #" & strDateTo & "# And Weekday(" & cstrFieldHoliday & ", 2) <= " & cbytWorkdaysOfWeek & ""
    lngHolidays = DCount("*", cstrTableHoliday, strFilter)
  End If
  
  ISO_WorkdayDiff = lngDays - lngHolidays
End Function
ccto
 

Excel Facts

What did Pito Salas invent?
Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.
You don't say if you're concerned about excluding statutory holidays and/or weekends or what. If so, you have a table for records that list all the holidays?
If you don't care about all that, then the DateDiff function can give you the hours, which you can divide by 24 to get the days, and the remainder would be the hours of any part days.
 
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