2 cubic equations 2 unknowns

ValGaug

New Member
Joined
Oct 11, 2017
Messages
1
Hey all,

I would like to resolve this equation in VBA but without using solver tool:

δ (2 - α²δ (2 - α)) / (α²δ² + 3 (α - 2αδ + δ)) = 4ξ
α (2 - αδ² (2 - δ)) / (α²δ² + 3 (α - 2αδ + δ)) = 4η

My unknowns are δ and α. We know ξ and η.

I know it's mainly a mathematical resolution but if you know anything which could help me I'd be glad to hear it.

Thank you

 

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