{1;2;3;4;5;6;7;8;9;10} to {1;2;0;0;0;6;7;0;0;10}
Posted by Somkiat on December 26, 2001 12:14 AM
Cell A1:A10 has number 1:10
B1 = 3
C1 = 5
B2 = 8
C2 = 9
I use this array formula
{=IF(((A1:A10<B1)+(A1:A10>C1))*((A1:A10<B2)+(A1:A10>C2)),A1:A10,0)}
to get {1;2;0;0;0;6;7;0;0;10}
which makes number 3 to 5 and number 8 to 9 to be 0 instead.
Is there any shorter array formula?
My real situation has number from 150 to 25000 that need to replace number from 200-250, 400-570, 15000-16000, 21200-23400 to be 0. Interval of 0 may be change and/or increase/decrease in future.
I understand deeply enough for array and vba. Please advise array formula.
Thanks,
Somkiat